Same would need to get at least a 95% on the next test, if he would like to receive a total average of an 80%
Answer:
I think the answer is option A
Answer:
Step-by-step explanation:
From the picture attached,
∠4 = 45°, ∠5 = 135° and ∠10 = ∠11
Part A
∠1 = ∠4 = 45° [Vertically opposite angles]
∠1 + ∠3 = 180° [Linear pair of angles]
∠3 = 180° - ∠1
= 180° - 45°
= 135°
∠2 = ∠3 = 135° [Vertically opposite angles]
∠8 = ∠5 = 135° [Vertically opposite angles]
∠5 + ∠6 = 180° [Linear pair of angles]
∠6 = 180° - 135°
∠6 = 45°
∠7 = ∠6 = 45° [Vertically opposite angles]
By triangle sum theorem,
m∠4 + m∠7 + m∠10 = 180°
45° + 45° + m∠10 = 180°
m∠10 = 180° - 90°
m∠10 = 90°
m∠10 = m∠12 = 90° [Vertically opposite angles]
m∠10 = m∠11 = 90° [Given]
Part B
1). ∠1 ≅ ∠4 [Vertically opposite angles]
2). ∠7 + ∠5 = 180° [Linear pair]
3). ∠9 + ∠10 = 180° [Linear pair]
Answer:
(2x-5)(3x-2)
Step-by-step explanation:
1)When factoring quadratic equations in for ax²+bx+c you need to separate the b term in a way that the two addends you separate it by should equal a•c. Just do trial and error. In this case you should get -4 and -15. Your separated equation should be:
6x²-4x-15x+10
2)now factor out a common factor from the first two terms and one from the last two terms you should have:
2x(3x-2)-5(3x-2)
3)finally rewrite this equation into two separate factors and you have your answer.
Answer:
Five thousand one hundred twenty nine and three hundred forty thousandths.
I believe that should be right!