Answer:
101.9 sq ft
Step-by-step explanation:
The figure is missing: find it in attachment.
Here we want to find the lateral surface area of the figure, which is the sum of the areas of all faces.
We have in total 5 faces:
- 1 of them is rectangle with sizes (8.5 ft x 3.3 ft), so its area is
![A_1=8.5 \cdot 3.3 =28.1 ft^2](https://tex.z-dn.net/?f=A_1%3D8.5%20%5Ccdot%203.3%20%3D28.1%20ft%5E2)
- 1 of them is a rectangle with sizes (3.3 ft x 5.1 ft), so its area is
![A_2 = 3.3\cdot 5.1 =16.8 ft^2](https://tex.z-dn.net/?f=A_2%20%3D%203.3%5Ccdot%205.1%20%3D16.8%20ft%5E2)
- 1 of them is a rectangle with sizes (6.8 ft x 3.3 ft), so its area is
![A_3 = 6.8\cdot 3.3 =22.4 ft^2](https://tex.z-dn.net/?f=A_3%20%3D%206.8%5Ccdot%203.3%20%3D22.4%20ft%5E2)
- Finally, we have 2 triangular faces (top and bottom), so their area is
![A_T=\frac{1}{2}bh](https://tex.z-dn.net/?f=A_T%3D%5Cfrac%7B1%7D%7B2%7Dbh)
where
b = 5.1 ft is the base
h = 6.8 ft is the height (because the triangle is a right triangle)
So the area of the triangle is
![A_T=\frac{1}{2}(5.1)(6.8)=17.3 ft^2](https://tex.z-dn.net/?f=A_T%3D%5Cfrac%7B1%7D%7B2%7D%285.1%29%286.8%29%3D17.3%20ft%5E2)
So the total lateral surface area of the figure is:
![A=A_1+A_2+A_3+2A_T=28.1+16.8+22.4+2(17.3)=101.9 ft^2](https://tex.z-dn.net/?f=A%3DA_1%2BA_2%2BA_3%2B2A_T%3D28.1%2B16.8%2B22.4%2B2%2817.3%29%3D101.9%20ft%5E2)