Answer:
The company should take a sample of 148 boxes.
Step-by-step explanation:
Hello!
The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.
They estimated a "pilot" proportion of p'=0.20
And using a 90% confidence level the CI should have a margin of error of 2% (0.02).
The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"
[p' ±
]
Where
p' is the sample proportion/point estimator of the population proportion
is the margin of error (d) of the confidence interval.

So






n= 147.28 ≅ 148 boxes.
I hope it helps!
Answer:
y = 2x^2 - 12x + 27
Step-by-step explanation:
<u>Step 1: Distribute the power</u>
y = 2(x - 3)² + 9
y = 2(x^2 - 6x + 9) + 9
y = 2x^2 - 12x + 18 + 9
y = 2x^2 - 12x + 27
Answer: y = 2x^2 - 12x + 27
Answer:
It must travel through a medium
Step-by-step explanation: Because I said so >:(
The minimum number of times would be 5 times.