No they are have a great day
Answer:
y=x-1
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
Using a calculator or a pencil, find each square root, including
three (3) decimal places. A negative number has no real square
roots, so skip '-71' and '-19'.
For each square root . . .
-- If the digits in the 2nd and 3rd decimal place are 00 through 24, then
make the 2nd decimal place a '0' and discard the rest.
-- If the digits in the 2nd and 3rd decimal place are 25 through 74, then
make the 2nd decimal place a '5' and discard the rest.
-- If the digits in the 2nd and 3rd decimal place are 75 through 99, then
increase the 1st decimal place by 1, make the 2nd decimal place a '0',
and discard the rest.
Answer:
46%
Step-by-step explanation:
<u>Step 1: Make an expression</u>
<u />
<u>Step 2: Divide both sides by 39</u>
<u />
<u>Step 3: Find the percent</u>
<u />
-> Gives us the increased percent
46%
Answer: 46%
