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loris [4]
3 years ago
8

What are the factors of expression (y-3)(x+7)

Mathematics
1 answer:
torisob [31]3 years ago
4 0
That is easy!! :)
y=3 and x=-7

When you find the factors of something like this, you have to just get the letter alone.

For example: y-3. You have to first write it as y-3=0, then you add 3 from BOTH sides of the = so that you can make the -3 go away and y will be alone. So, it will look like this: y-3+3=0+3. Then, you solve it for y (which just means that you want y by itself on one side of the = ). So, -3+3=0, which means they disappear from that side; since 0+3=3, that's what that side turns into, so what you end up with is y=3

Same thing goes for the x+7 equation:
x+7=0
x+7-7=0-7
x=-7
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sertanlavr [38]
-9

There are the same signs so you'd just add them together and use whatever sign they are..
7 0
3 years ago
PLEASE HELP
qaws [65]
NUMBER ONE IS THE RIGHT ANGLE AND THE SECIND INE IS SUPPLEMENTARY
8 0
3 years ago
Require help with this question
user100 [1]
A) There are a number of ways to compute the determinant of a 3x3 matrix. Since k is on the bottom row, it is convenient to compute the cofactors of the numbers on the bottom row. Then the determinant is ...
  1×(2×-1 -3×1) -k×(3×-1 -2×1) +2×(3×3 -2×2) = 5 -5k

bi) Π₁ can be written using r = (x, y, z).
  Π₁ ⇒ 3x +2y +z = 4

bii) The cross product of the coefficients of λ and μ will give the normal to the plane. The dot-product of that with the constant vector will give the desired constant.
  Π₂ ⇒ ((1, 0, 2)×(1, -1, -1))•(x, y, z) = ((1, 0, 2)×(1, -1, -1))•(1, 2, 3)
  Π₂ ⇒ 2x +3y -z = 5

c) If the three planes form a sheath, the ranks of their coefficient matrix and that of the augmented matrix must be 2. That is, the determinant must be zero. The value of k that makes the determinant zero is found in part (a) to be -1.

A common approach to determining the rank of a matrix is to reduce it to row echelon form. Then the number of independent rows becomes obvious. (It is the number of non-zero rows.) This form for k=-1 is shown in the picture.

5 0
3 years ago
A pumpkin is launched directly upwards at 72 feet per second from a platform 24 feet high. The pumpkins height, h, at time t sec
STALIN [3.7K]

Answer: Maximum height =  105 feet

And, It takes 9/4 seconds to reach that point.

Step-by-step explanation:

Here the given function that shows the height of the pumpkin,

h(t) = -16t^2 + 72t + 24 --------(1)

Where t is the time in second.

Differentiating equation (1) with respect to t,

We get,    h'(t) = -32 t + 72

Again differentiating above equation with respect to t,

We get,   h''(t) = -32

For maximum or minimum,    h'(t) = 0

- 32 t + 72 = 0

32 t = 72

t = \frac{9}{4}

At t = 9/4 , h''(t) = Negative value,

Therefore, At t = 9/4 seconds, h(t) is maximum,

And, the maximum value is,

h(\frac{9}{4} ) = -16(\frac{9}{4})^2 + 72(\frac{9}{4}) + 24

h(\frac{9}{4} ) = -16(\frac{81}{16})+ 72(\frac{9}{4}) + 24

h(\frac{9}{4} ) = -81 + 162 + 24=105

Therefore, the maximum height of the pumpkin is 105 feet at 9/4 seconds

8 0
3 years ago
Find the value of x if 8∧3x/2∧10 = 4∧2x/16
solniwko [45]

Answer:

Solve for

x

by cross multiplying.

Exact Form:

x=

6/5

Decimal Form:

x=

1.2

Mixed Number Form:

x=

1 1/5

6 0
3 years ago
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