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3 years ago

How many significant digits are there in 17.0

1 answer:

4 0

The answer is three significant figures. The 1 and the 7 are both significant, because they are non-zero quantities.
This is where significant figures gets a little more complicated, because if a zero is used as a placeholder (i.e. 0.00027 cm) then it is insignificant.
But in the case above, the zero isn't being used as a placeholder, and thus, is significant.

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If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

5 0

3 years ago

Order of operations<br> 4/7÷1 1/7+5

Debora [2.8K]

First 4/7 times 7/11 and plus 5,the result of 4/7 times 7/11 equal 4/11,AND THEN 4/11 PLUS 5 EQUAL 5 AND 4/11

7 0

3 years ago

A rectangular pool is 30 1/3 feet long and 12 1/2 feet wide. What is the area of the pool?

butalik [34]

About 379.1666666666666
The 6 is repeating. Or about 379 if your rounding.

4 0

3 years ago

An astronaut visited Mars. His weight on Earth was 180 pounds, and his weight on Mars was only 72 pounds. He removed a rock with

Damm [24]

Find the percentage of ratio to weight.

180/72 = 2.5

So 2.5 Earth Pounds = 1 Mars Pound

16*2.5 = 40 Pounds the rock weighs on earth.

5 0

3 years ago

8/9=x+1/3(7) how to solve

Debora [2.8K]

Do 1/3 x 7 (due to the parentheses which mean multiplication). Once you get that answer you should have 8/9 = x + (answer). Now subtract that answer from 8/9 and that's your x!

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3 years ago