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VikaD [51]
3 years ago
6

Can you please help with the answer

Mathematics
1 answer:
sertanlavr [38]3 years ago
8 0

11w times 6x

240w times 18y

you always use the last numbers and that would equal...

____________________________________________________________

66x times 4320y=

285120 divide it by 6= 47520

then by 12

47520 divided by 12=

3960-80= 3880

3880 divided by 16 times 4

your answer is 970y

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puteri [66]
A kid has $1 and he receives $1 everyday after doing his homework. So the initial money that he has is the y-intercept and the money that he receives everyday is the slope.

Hope this helps :)
6 0
3 years ago
What is the solution to the system of equations graphed below?<br> y=-4x + 33<br><br> y=5/3x-1
Black_prince [1.1K]

Answer:

x = 6

y = 9

This is the correct answer. Not satisfied? Check out this answer expert verified answer of the same question but with a step-by-step explanation. This answer is just a simple version of rocioo's correct answer.

Expert Verified Answer (of this same question but with a step-by-step explanation):

This is the link to rocioo's answer. <u>brainly.com/question/13675950</u>

3 0
3 years ago
Read 2 more answers
Pls help:((((
Fiesta28 [93]

Answer: B

Step-by-step explanation:

l = 2

2 ( l + w ) = 48 , or , l + w = 24

w = 8 , & , so , l = 2 w = 16  inches.

4 0
3 years ago
Use this information to answer the questions. University personnel are concerned about the sleeping habits of students and the n
Oksanka [162]

Answer:

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

Step-by-step explanation:

1) Data given and notation

n=377 represent the random sample taken

X=209 represent the students reported experiencing excessive daytime sleepiness (EDS)

\hat p=\frac{209}{377}=0.554 estimated proportion of students reported experiencing excessive daytime sleepiness (EDS)

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

6 0
3 years ago
A youth soccer field is a rectangle 110 yards long and 60 yards wide. A professional soccer field is a rectangular 110 yards lon
Ksivusya [100]

Answer:

2200 Square Yards

Step-by-step explanation:

Dimension of the Youth Soccer Field = 110 yards long and 60 yards wide.

  • Therefore Area of the Youth Soccer Field = 110 X 60 =6600 Square Yards

Dimension of the professional soccer field =110 yards long and 80 yards wide.

  • Area of the professional soccer field = 110 X 80 =8800 Square Yards

The difference in their Area = 8800-6600=2200 Square Yards

Therefore, the professional soccer field has an area of 2200 Square Yards more than the youth soccer field.

4 0
3 years ago
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