Can you please help with the answer

How do you write the decimal 0.7 as a fraction in simplest form

puteri [66]

0.7 is 7/10 in fraction form

It is also already in simplest form

7/10 is your answer

hope this helps

4 0

3 years ago

PLEASE HELP. WILL MARK BRAINLIEST IF CORRECT

Luda [366]

9514 1404 393

Answer:

(b) Congruent Figures

Step-by-step explanation:

Reflections, rotations, and translations are called "rigid transformations" because they do not change the size or shape of the figure. The image is always congruent to the original.

On the other hand, dilations change the size of the figure, so the image is <em>not congruent</em> with the original.

Rigid transformations result in congruent figures.

6 0

3 years ago

A group of retired admirals, generals, and other senior military leaders, recently published a report, "Too Fat to Fight". The r

weqwewe [10]

Answer:

$z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735$

$p_v =P(z$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .

Step-by-step explanation:

1) Data given and notation

n=180 represent the random sample taken

X=125 represent the number of americans between 17 to 24 that not qualify for the military

$\hat p=\frac{125}{180}=0.694$ estimated proportion of americans between 17 to 24 that not qualify for the military

$p_o=0.75$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that less than 75% of Americans between the ages of 17 to 24 do not qualify for the military :

Null hypothesis: $p\geq 0.75$

Alternative hypothesis: $p < 0.75$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .

6 0

3 years ago

Paige wants to sew lace around a round table cloth. The table cloth has a diameter of 6ft. About how much lace will Paige need?

Free_Kalibri [48]

It is B because u need enough for it to do it right

5 0

2 years ago

David wants to my have a board for $398.50. He has saved $350 so far. Stores offering a discount for 15% for the month of Januar

bija089 [108]

Answer:

Yes, he will

Step-by-step explanation:

398.50 x .15 = 59.775

398.50-59.775=338.725

350>338.725

5 0

3 years ago