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ZanzabumX [31]
3 years ago
13

Consider the probability that at least 96 out of 152 computers will not crash in a day. Assume the probability that a given comp

uter will not crash in a day is 66%.Approximate the probability using the normal distribution. Round your answer to four decimal places.
Mathematics
1 answer:
djyliett [7]3 years ago
6 0

Answer:

0.2061

Step-by-step explanation:

Probability (no crash) = 66% = 0.66

Average (no crash) expected out of 152 computers = 0.66 (152) = 100.32

Standard deviation 's' =  √ [ (154) (0.66) (1-0.66) ] = √ (154) (0.66) (0.34)

=  √ 34.5576 = 5.87

P (x <u>></u> 96) = 1 - P (x <u><</u> 95)

z= (x - u) / s ;  x = sample mean = 95.5 (continuity correction factor = 0.5) ,   u = population average = 100.32

z = (95.5 - 100.32) / 5.87 = 4.82 / 5.87 = 0.82

P (x <u><</u> 95) = P (z <u><</u> 0.82) = 0.7939

P (x <u>></u> 96) = 1 -  0.7939  = 0.2061

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A normally distributed data set has a mean of 0 and a standard deviation of 2. The closest to the percent of values between -4.0 and 2.0 would be 84%.

<h3>What is the empirical rule?</h3>

According to the empirical rule, also known as the 68-95-99.7 rule, the percentage of values that lie within an interval with 68%, 95%, and 99.7% of the values lies within one, two, or three standard deviations of the mean of the distribution.

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A normally distributed data set has a mean of 0 and a standard deviation of 2.

Z=(x-\mu)/\sigma

P(x=-0.4)\\\\z=(-0.4-0)/2\\\\= -0.2\\\\P(x=2)\\z=(2-0)/2\\\\=1

P(-0.4 < x < 2)=p(-0.2 < z < 1)=p(-0.2 < z < 0)+p(0 < z < 1)……….(by symmetry)

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What is the shape of the normal distribution?

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