Answer:
12n + 60
General Formulas and Concepts:
<u>Pre-Algebra</u>
Distributive Property
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
(n + 12) × 5 + 7n
<u>Step 2: Simplify</u>
- Distribute 5: 5(n) + 5(12) + 7n
- Multiply: 5n + 60 + 7n
- Combine like terms: 12n + 60
Answer:


Step-by-step explanation:
Given the matrices


Calculating AB:

Multiply the rows of the first matrix by the columns of the second matrix


Hence,

Therefore,


Answer:
-40 < x < 20
Step-by-step explanation:
step 1: -12 < 1/2(x+16) < 18 --> Distribute
step 2: -12 < 1/2x + 8 < 18 --> subtract 8
step 3: -20 < 1/2x < 10 --> Multiply by 2
answer : -40 < x < 20
Answer:
Step-by-step explanation:
Since 2 of the 3 binomials are identical I would start the distribution there.
(1 + 4i)(1 + 4i) = 
I'm sure you have learned in class by now that i-squared is = to -1, so we can make that substitution:
1 + 8i + 16(-1) which simpifies to
1 + 8i - 16 which simplifies further to
-15 + 8i. Now we need to FOIL in the last binomial:
(-15 + 8i)(-4 + 4i) = 
Combine like terms to get

Again make the substitution of i-squared = -1:
60 - 92i + 32(-1) which simplifies to
60 - 92i - 32 which simpifies, finally, to a solution of:
28 - 92i