Use the image to answer the question.

3. For the polynomial: ()=−2(+19)3(−14)(+3)2, do the following:A. Create a table of values that have the x-intercepts of p(x) in

Pepsi [2]

Part A. We are given the following polynomial:

$\mleft(\mright)=-2\mleft(+19\mright)^3\mleft(-14\mright)\mleft(+3\mright)^2$

This is a polynomial of the form:

$p=k(x-a)^b(x-c)^d\ldots(x-e)^f$

The x-intercepts are the numbers that make the polynomial zero, that is:

$\begin{gathered} p=0 \\ (x-a)^b(x-c)^d\ldots(x-e)^f=0 \end{gathered}$

The values of x are then found by setting each factor to zero:

$\begin{gathered} (x-a)=0 \\ (x-c)=0 \\ \text{.} \\ \text{.} \\ (x-e)=0 \end{gathered}$

Therefore, this values are:

$\begin{gathered} x=a \\ x=c \\ \text{.} \\ \text{.} \\ x=e \end{gathered}$

In this case, the x-intercepts are:

$\begin{gathered} x=-19 \\ x=14 \\ x=-3 \end{gathered}$

The multiplicity are the exponents of the factor where we got the x-intercept, therefore, the multiplicities are:

Part B. The degree of a polynomial is the sum of its multiplicities, therefore, the degree in this case is:

$\begin{gathered} n=3+1+2 \\ n=6 \end{gathered}$

To determine the end behavior of the polynomial we need to know the sign of the leading coefficient that is, the sign of the coefficient of the term with the highest power. In this case, the leading coefficient is -2, since the degree of the polynomial is an even number this means that both ends are down. If the leading coefficient were a positive number then both ends would go up. In the case that the leading coefficient was positive and the degree and odd number then the left end would be down and the right end would be up, and if the leading coefficient were a negative number and the degree an odd number then the left end would be up and the right end would be down.

Part C. A sketch of the graph is the following:

If the multiplicity is an odd number the graph will cross the x-axis at that x-intercept and if the multiplicity is an even number it will tangent to the x-axis at that x-intercept.

6 0

1 year ago

Does this graph show a function? Explain how you know.

Sav [38]

A. It passes the vertical line test

4 0

2 years ago

For the following rectangular prism, drag and drop the steps needed to find the volume in the correct order. Then type the volum

Kamila [148]

Answer:

Volume = 100 $in^{3}$

Step-by-step explanation:

Volume, V= Bh

length = 10 inches

width = 5 inches

height = 2 inches

So that,

B = 5(10)

= 50 $in^{2}$

B = 50 $in^{2}$

Then,

V = (50)(2)

= 100

v = 100 $in^{3}$

5 0

2 years ago

Consider the function represented by 9x+3y= 12 with x as the independent variable. How can this function be written using

Ivenika [448]

Answer:

f(x)=-3x+4

(can't see some of your choices)

Step-by-step explanation:

We want x to be independent means we want to write it so when we plug in numbers we can just choose what we want to plug in for x but y's value will depend on our choosing of x.

So we need to solve for y.

9x+3y=12

Subtract 9x on both sides

3y=-9x+12

Divide both sides by 3:

y=-3x+4

Replace y with f(x).

f(x)=-3x+4

6 0

2 years ago

d)An insurance company will only sell its Select policy to people for whom the probability of a stroke in the next 10 years is l

NARA [144]

Answer:

Check the explanation

Step-by-step explanation:

The First action is to enter the data in Excel and then save it as a csv file. Then call the data set in R using your saved path, I have made use of my computer path here in my code. please change it for yours.

Here is the code That you need to use for finding the multiple limear regression model and summary of it.

code:

data=read. csv("C:\\Users\\HP\\Desktop\\chegg. csv")

data

attach(data)

model=lm(Risk~Age+Blood.Pressure+Smoker)

summary(model)

And Here is the output:

Call:

lm(formula = Risk ~ Age + Blood.Pressure + Smoker)

Residuals:

Min 1Q Median 3Q Max

-13.1064 -1.5715 0.4225 3.4855 8.5561

Coefficients:

Estimate Std. Error t value Pr(>|t|)

(Intercept) -91.75950 15.22276 -6.028 1.76e-05 ***

Age 1.07674 0.16596 6.488 7.49e-06 ***

Blood.Pressure 0.25181 0.04523 5.568 4.24e-05 ***

Smoker 8.73987 3.00082 2.912 0.0102 *

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 5.757 on 16 degrees of freedom

Multiple R-squared: 0.8735, Adjusted R-squared: 0.8498

F-statistic: 36.82 on 3 and 16 DF, p-value: 2.064e-07

The answer is now written in the notebook which i am uploading..

6 0

2 years ago