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Lerok [7]
2 years ago
7

Annora bought a box of cookies that matches the dimensions of the solid below. How many square units of cardboard were used to c

onstruct the box? If your solution is not a whole number, round to the nearest tenth. Help pls
Mathematics
1 answer:
Mandarinka [93]2 years ago
4 0
92is the correct answer
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PLEASE HELP ASAP TENTH GRADE GEOMETRY
wel

Answer: SU = 4(1) + 1 = 5

Step-by-step explanation:

Since T is on segment SU we know the whole is eqaul to the sum of it’s parts.

ST + TU = SU substitute

3x - 1 + 3x = 4x + 1 simplify

6x - 1 = 4x + 1 solve for x

2x = 2

x = 1

ST = 3(1) -1 = 2

TU = 3(1) = 3

SU = 4(1) + 1 = 5

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3 years ago
PLEASE HELP WITH THIS QUESTION
DedPeter [7]

I think the correct answer is c

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3 years ago
PLEASE HELP 30 PTS!!!
polet [3.4K]

if she bought the shirts you have to double 3:50 which equals $7 so double 7 it is 14. So Dave spend half that amount which would be 3:50

8 0
3 years ago
Read 2 more answers
The graph of a sinusoidal function intersects its midline at (0,5) and then has a maximum point at (\pi,6)
Natalija [7]
First, let's use the given information to determine the function's amplitude, midline, and period. 

Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.

Finally, we should determine the parameters of the function's formula by considering all the above.
     
                      Determining the amplitude, midline, and period 

The midline intersection is at y=5 so this is the midline. 

The maximum point is 1 unit above the midline, so the amplitude is 1. 

The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
 
                            Determining the type of function to use 

Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function. 

This means there's no horizontal shift, so the function is of the form -

a sin(bx)+d

Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.

The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1. 

The midline is y=5, so d=5. 

The period is 4π so b = 2π / 4π = 1/2 simplified. 

f(x)1 sin   (\dfrac{1}{3}x) +5  = Solution
8 0
3 years ago
The average student-loan debt is reported to be $25,235. A student believes that the student-loan debt is higher in her area. Sh
yulyashka [42]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 25235

For the alternative hypothesis,

µ > 25235

This is a right tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 100,

Degrees of freedom, df = n - 1 = 100 - 1 = 99

t = (x - µ)/(s/√n)

Where

x = sample mean = 27524

µ = population mean = 25235

s = samples standard deviation = 6000

t = (27524 - 25235)/(6000/√100) = 3.815

We would determine the p value using the t test calculator. It becomes

p = 0.000119

Since alpha, 0.05 > than the p value, 0.000119, then we would reject the null hypothesis. There is sufficient evidence to support the claim that student-loan debt is higher than $25,235 in her area.

6 0
3 years ago
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