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Contact [7]
3 years ago
11

Which would not be a step in solving 18= 24(4+x)?

Mathematics
1 answer:
sweet [91]3 years ago
5 0

Answer:

doop

Step-by-step explanation:

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Solve the following by completing the square.
sertanlavr [38]

I think it might be D. I'm just giving an educated guess.

6 0
2 years ago
Tamara earns $8 an hour at her job working 25 hours per week. If 22% of her paycheck goes to taxes, what is Tamara’s monthly cas
DerKrebs [107]

To solve this problem you must apply the proccedure shown below:

1. First, you must multiply $8 by the hours given in the exercise:

(8dollars)(25hours)=200dollars

2. Now, multiply the result obtained above by 4, to calculate her monthly income:

(200dollars)(4)=800dollars

3. If 22% of her paycheck goes to taxes, you have:

(800dollars)-[(800dollars)(0.22)]=624dollars

Therefore, the answer is: $624

5 0
3 years ago
Find the surface area of the solid shown or described. If necessary, round to the nearest tenth. Use the formula, write it out,
Mkey [24]
\bold{ANSWER:}
163.9 m^2

\bold{SOLUTION:}

7 0
2 years ago
Eduardo has to make a 10 minute video of his test corrections for his Algebra 2 teacher in order to be eligible to retest. His t
shutvik [7]

Answer:

7 ≤ v ≤ 13

Step-by-step explanation:

Length of video required must be within 10 minutes

Submitted length of video must be with 3 minutes of the 10 minutes video

To create an absolute value inequality :

Let v = the range of value for which the required video will be :

|v - 10| = ±3

Lower boundary :

|v - 10| = - 3

v = - 3 + 10

v = 7

Upper boundary :

|v - 10| = 3

v = 3 + 10

v = 13

Hence,

7 ≤ v ≤ 13

4 0
3 years ago
A rectangular solid has width w, a length of 7 more than the width, and a height that is equivalent to 15 decreased by 3 times t
dexar [7]

Answer:

For a rectangular solid with:

width = w

length = l

height = h

The volume is equal to:

V = w*l*h

in this case we know that:

width = w.

"length of 7 more than the width"

l = w + 7.

"a height that is equivalent to 15 decreased by 3 times the width."

h = 15 - 3*w

Then the volume will be:

V = w*l*h = w*(w + 7)*(15 - 3w) = (w^2 + 7*w)*(15 - 3*w)

V =  ( -3*w^3 + 15*w^2 + 105*w - 21*w^2)

V = (-3*w^3 - 6*w^2 + 105*w)

Now, the maximum volume will be for the value of w such that:

V'(w) = 0.

and:

V''(W) < 0

Where:

dV/dw = V'(w).

dV'/dw = V''(w)

Then first we need to differentiate the equation for the volume.

V'(w) = dV/dw = ( 3*(-3*w^2) + 2*(-6*w) + 105)

V'(w) = -9*w^2 - 12*w + 105.

Then we need to find the solution for:

-9*w^2 - 12*w + 105 = 0.

We can use the Bhaskara formula, and we will get:

w = \frac{+12 +-\sqrt{(-12)^2 - 4*(-9)*105} }{2*-9}  = \frac{+12 +- 62.6}{-18}

Then the two solutions are:

w₁ = (+12 - 62.6)/(-18) = 2.81

w₂ = (+12 + 62.6)/(-18) = -15.5

But we can not have a negative width, so we can just discard the second solution.

Now let's check the second condition for the maximum, we must have:

V''(2.81) < 0.

V'' = dV'/dw = 2*(-9*w) - 12 = -18*w - 12

V''(2.81) = -18*2.81 - 12 = -62.58 < 0 .

Then the volume is maximized when w = 2.81, and the maximum volume will be:

V(2.81) =  (-3*(2.81)^3 - 6*(2.81)^2 + 105*2.81) = 180.1

 

8 0
2 years ago
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