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uysha [10]
3 years ago
13

Which operation would be completed second in the following expression?

Mathematics
1 answer:
butalik [34]3 years ago
3 0

Answer:

I THINK IT WILL BE HELPFUL

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What's the answer ?<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B255%20-%2030%7D%20" id="TexFormula1" title=" \sqrt{255
Aloiza [94]

Answer:

\sqrt 255-30

= -14.0312805773

7 0
3 years ago
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Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
3 years ago
The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. (a) Determine the
maxonik [38]

Answer:

a) 0.5 = 50% of flanges exceed 1 millimeter.

b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

P(X > x) = \frac{b - x}{b - a}

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

This means that a = 0.95, b = 1.05

(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5

0.5 = 50% of flanges exceed 1 millimeter.

(b) What thickness is exceeded by 90% of the flanges?

This is x for which:

P(X > x) = 0.9

So

\frac{1.05 - x}{1.05 - 0.95} = 0.9

1.05 - x = 0.9*0.1

x = 1.05 - 0.9*0.1

x = 0.96

A thickness of 0.96 millimeters is exceeded by 90% of the flanges

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3 years ago
Which area model can u use to fine * find 39 x73
sweet [91]
The area model you can use is D , cs 70 +3 & 30+9
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Lance is swimming at the country club swimming pool. The pool is 30 feet wide and 100 feet long. If Lance swims the diagonal len
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Lance Will Swim 30 ft. Im Not Sure.
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