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atroni [7]
4 years ago
14

In humans, "unattached" earlobes are dominant over "attached" earlobes. "Widows peak" hairline is dominant over "non-widows peak

" hairline. Use E and e for the earlobe phenotype alleles, and W and w for the hairline phenotype alleles. A female and a male, both with genotype EeWw have a child. What is the probability it will be a boy, and have attached earlobes and a widows peak hairline?

Biology
1 answer:
Andre45 [30]4 years ago
3 0

Answer:

3/32

Explanation:

<em>The probability would be 3/32</em>

From the illustration:

  • Unattached earlobe E is dominant over attached earlobe e.
  • Widows peak hairline is dominant over non-widows peak hairline.

EeWw and EeWw were crossed  (Assuming both traits are autosomal)

EeWw   x   EeWw

Progeny :

1 EEWW  - unattached earlobe with widows peak

2 EEWw -  unattached earlobe with widows peak

2 EeWW -  unattached earlobe with widows peak

4 EeWw -  unattached earlobe with widows peak

1 EEww -  unattached earlobe with non-widows peak

2 Eeww -  unattached earlobe with no-widows peak

1 eeWW  - attached earlobe with widows peak

2 eeWw - attached earlobe with widows peak

1 eeww - attached earlobe with no-widows peak

<u>Generally, the probability of obtaining a male or a female in a cross is 50/50 or 1/2.</u>

<u>From the crossing result, the probability of having attached earlobe and widows peak hairline is 3/16.</u>

<em>Hence, the probability of obtaining a boy with attached earlobes and widows peak airline:</em>

1/2 x 3/16 = 3/32.

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