Answer:
a: no solutions
b: (2, 3)
Step-by-step explanation:
a:
In both equations, the slope of x is the same, but the y-intercept is not, which means they are parallel. Therefore, this system of equations has no solutions.
b:
Since both of the equations are equal to y, we can set them equal to each other:
We can solve by factoring (by finding a number that multiplies to 4 and adds up to -4):
(x-2)^2 = 0
x = 2
Now, to find y, plug-in x to any of the equations:
y = 2*2-1 = 3
Therefore, the solution to this system of equation is (2, 3)
I hope this helped.
Answer:
yes it is because the second triangle is the base and the other three triangles are the sides of the three dimensional shape
We can see that there are 5 CDs, each of radius 9 cm
<u>Area occupied by 1 disc:</u>
Area of a circle = πr²
Area of disc = π(9)²
Area of disc = 3.14 * 81 = 254 cm²
<u>Area occupied by 5 discs:</u>
Area occupied by 5 discs = Area occupied by 1 disc * 5
Area occupied by 5 discs = 254 * 5
Area occupied by 5 discs = 1270 cm²
Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where 
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar
50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.
c)The expected number of grams to be eaten before encountering the first fragments :
s
Answer:
35
Step-by-step explanation:
