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guapka [62]
3 years ago
6

Which two square numbers add together to make 34?

Mathematics
1 answer:
const2013 [10]3 years ago
5 0
The two square numbers which add up to 34 is 9 and 25, since 3^2 is 9 and 5^2 is 25
You might be interested in
Cheryl painted her living room walls with two different colors. She painted part of the room yellow and another part green. If t
kramer

Answer:

Total percent of the room did she paint green = 60%

Step-by-step explanation:

Given - Cheryl painted her living room walls with two different colors. She painted part of the room yellow and another part green. If the surface area of the walls in her room is 720 ft² and she painted 288 ft² yellow.

To find - What percent of the room did she paint green ?

Proof -

Given that,

The surface area of the walls in her room = 720 ft²

Total area painted in yellow color = 288 ft²

So,

Total area painted in green color would be = 720 - 288 = 432 ft²

Now,

Let the total percent green color painted = x

So,

720 × x% = 432

⇒720*\frac{x}{100}  = 432

⇒ x = \frac{432*100}{720} = 60

∴ we get

Total percent of the room did she paint green = 60%

7 0
3 years ago
What is the standard form for 4x10,000+8x1,000+2x100+3x10+6x1+7x1/10
Andrei [34K]

Answer:

48,236.7

Step-by-step explanation:

40,000 + 8,000 + 200 + 30 + 6 + 7/10

7/10 can also be written .7

3 0
2 years ago
Your friend claims that there is not enough information given to find the value of x.Is your friend correct?
Kay [80]
No not a full question
6 0
4 years ago
What are the period and phase shift for f(x) = 3 tan(4x + π)?
Pie
For an equation y = a tan[b(x+c)], the period is equal to 2*pi/b, while the phase shift is c.
This equation can be rewritten as:
f(x) = 3 tan [4(x + pi/4)]
In this case, b = 4, c = pi/4
Then the period = 2*pi/b = pi/2.
The phase shift = pi/4 (to the left).
3 0
3 years ago
There is a mountain with 45 bat caves in a row. Every cave has at least 2 bats and there are 490 bats in all. Any 7 caves in a r
sergiy2304 [10]

Answer:

12 bats

Step-by-step explanation:

Let us number the bat caves from 1 to 45 and divide them into 5 parts:

a) 1

b) 2 to 29 (7\times 4=28 bats)

c) 30

d) 31 to 44 (7\times2=14 bats)

e) 45

It is given that any 7 caves in a row has 77 bats. Hence, the total number of bats in part b and d = (4\times77)+(2\times77)=462 bats.

There remains (490-462)=28 bats in cave number 1, 30 and 45.

Now, our question demands the maximum possible number of bats in cave 30.

Minimum number of bats in a cave is 2. So we shall put 2 bats in the last cave, which gives us 7\times2=14 bats in the first cave.

Therefore, the number of bats in cave number 30 = (28-2-14)=12 bats.

5 0
4 years ago
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