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STatiana [176]
3 years ago
10

which expression represents purely real numbers and which expression represents non-real complex number?​

Mathematics
1 answer:
Lyrx [107]3 years ago
6 0

Answer:

Step-by-step explanation:

Complex numbers are the numbers represented by the expression = a + bi

Here a = real part of the number

bi = imaginary part

a and b are the real numbers.

i^9=(i^2)^4.(i)

    =(-1)^{4}.i [Since, i^2=-1]

    =i

Therefore, its a non real complex number.

2 - \sqrt{-49} = 2-\sqrt{(-1)(7)^2}

               = 2-7\sqrt{-1}

               = 2-7i

This number is a Non real complex number.

\sqrt{(-18)^2}=18\sqrt{-1}

              = 18i

It's a non real complex number.

3 + 2i

It's a non real complex number.

-289

It's a purely real number.

4-32i^2=4-32(-1)

             = 4 + 32

             = 36

It's a purely real number.

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Answer:

1\4

Step-by-step explanation:

i did it out of 100 i choose 25/100

then id you simplified that 25 goes into 100 4 times 25 goes into int self one time so the answer is 1/4

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Expand the function f(x)=(3x+2)^4 with the binomial theorem, not factored
lozanna [386]

Step-by-step explanation:

Enter a problem...

Algebra Examples

Popular Problems

 

Algebra

 

Expand using the Binomial Theorem (3x+2)^4

(3x+2)4(3x+2)4

Use the binomial expansion theorem to find each term. The binomial theorem states (a+b)n=n∑k=0nCk⋅(an−kbk)(a+b)n=∑k=0n⁡nCk⋅(an-kbk).

4∑k=04!(4−k)!k!⋅(3x)4−k⋅(2)k∑k=04⁡4!(4-k)!k!⋅(3x)4-k⋅(2)k

Expand the summation.

4!(4−0)!0!⋅(3x)4−0⋅(2)0+4!(4−1)!1!⋅(3x)4−1⋅(2)+4!(4−2)!2!⋅(3x)4−2⋅(2)2+4!(4−3)!3!⋅(3x)4−3⋅(2)3+4!(4−4)!4!⋅(3x)4−4⋅(2)44!(4-0)!0!⋅(3x)4-0⋅(2)0+4!(4-1)!1!⋅(3x)4-1⋅(2)+4!(4-2)!2!⋅(3x)4-2⋅(2)2+4!(4-3)!3!⋅(3x)4-3⋅(2)3+4!(4-4)!4!⋅(3x)4-4⋅(2)4

Simplify the exponents for each term of the expansion.

1⋅(3x)4⋅(2)0+4

Hope this helps!

8 0
3 years ago
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What is the vertex of this quadratic function? f(x) = 10x2 + 5x − 7 A. (0.25, -5.250) B. (0.25, -7.625) C. (-0.25, -5.250) D. (-
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E

Given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then

The x-coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = 10x² + 5x - 7 is in standard form

with a = 10, b = 5 and c = - 7, hence

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Substitute this value into the equation for y-coordinate

y = 10 (- \frac{1}{4})² + 5 (- \frac{1}{4}) - 7

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  = \frac{5}{8} - \frac{10}{8} - \frac{56}{8} = - \frac{61}{8}

vertex = (- 0.25, - 7.625 ) → E



6 0
3 years ago
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