A book had a lenght of 5 inches and a width of 10 inches. What is the area of the book
1 answer:
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Answer:
4.75 inches.
Step-by-step explanation:
We must introduce the symbols for inches and feet.
Here we will use, x' = x feet and x" = x inches
A high school track teams long jump record is 21 feet and inches i.e. 21'2.25" this year.
Now, Tim's best long jump is 20 feet and inches i.e. 20'9.5".
So, the difference between the record jump and Tim's best jump is
(21'2.25" - 20'9.5")
= (21'2.25" - 21') + (21' - 20'9.5")
= 2.25" + 2.5" {Since, 1' = 12" i.e. 21' = 20' 12"}
= 4.75"
Therefore, Tim has to jump 4.75 inches farther to break the record. (Answer)
Answer:
424 cm²
Step-by-step explanation:
The figure is composed of a square and a trapezium on top
A of square = 18² = 324 cm²
A of trapezium = h (b₁ + b₂ )
where h is the perpendicular height and b₁, b₂ the parallel bases
Here h = 8, b₁ = 18 and b₂ = 7 , then
A = 0.5 × 8 × (18 + 7) = 4 × 25 = 100 cm²
Area of hexagonal park = 324 + 100 = 424 cm²