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777dan777 [17]
3 years ago
13

Pam and her brother both open savings accounts. Each begin with a balance of zero dollars. For every two dollars that Pam save i

n her account, her brother save five dollars in his.
Mathematics
1 answer:
dezoksy [38]3 years ago
6 0

Answer:

Ratio [Pam to her brother] = 2:5

Step-by-step explanation:

Given:

Pam saves every two dollar

Her brother saves fives dollar (For every two dollar)

Find:

Ratio [Pam saving and his brothers saving]

Computation:

It is given that if Pam saves $2 her brother saves $5

So,

Ratio [Pam to her brother] = 2/5

Ratio [Pam to her brother] = 2:5

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If 5b=6a+16 and 9a=7b-20, then what are the values of a and b? show work.
Strike441 [17]

Answer:

a = 4, b = 8

Step-by-step explanation:

Rewrite 5b=6a+16 and 9a=7b-20 vertically:

5b=6a+16

9a=7b-20

Let's use substitution.  Solve the first equation for b:

       6a + 16

b = --------------

             5

Substitute this result into the second equation:

9a = 7(b) + 16, or

             6a + 16

9a = 7*-------------- - 20

                   5

Eliminate the fraction by multiplying all three terms by 5:

45a = 7(6a + 16) - 100, or

3a =        112 - 100, or:

3a = 12, which leads to a = 4.  

Find b by subbing 4 for a in either of the given equations:

5b = 6(4) + 16, or

5b = 40, leading to b = 8

The solution is a = 4, b = 8

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FromTheMoon [43]
1. -13<-26
2. -26>-13
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3 years ago
A faucet is used to add water to a large bottle that already contained some water. after it has been filling for 4 ​seconds, the
mina [271]
The problem gives us points (4, 12) and (11,26). We first find the slope using m=(y2-y1)/(x2-x1). We substitute and get m=(26-12)/(11-4). This simplifies to m = 2. We can then use the point-slope form y-y1 = m(x-x1). We substitute and get y - 12 = 2(x - 4). We distribute: y - 12 = 2x - 8. We add 12 to both sides to get our final answer, y = 2x + 4.
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Answer:

\huge\boxed{g(a-1)=\dfrac{2-a}{a}=\dfrac{2}{a}-1}

Step-by-step explanation:

g(t)=\dfrac{1-t}{1+t}\\\\g(a-1)-\text{substitute}\ t=a-1\ \text{to}\ g(t):\\\\g(a-1)=\dfrac{1-(a-1)}{1+(a-1)}=\dfrac{1-a-(-1)}{1+a+(-1)}=\dfrac{1-a+1}{1+a-1}=\dfrac{(1+1)-a}{(1-1)+a}=\dfrac{2-a}{a}

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5

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