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2 years ago

Counting with combinations

Mathematics

1 answer:

Paladinen [302]2 years ago

7 0

Answer:

Step-by-step explanation:

35 divided by 5 equals 7

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4. Sammy created a model of a frontier fort. He used a scale

alina1380 [7]

Answer:

18 ft. tall

Step-by-step explanation:

This is because if 1 in. equals 2 ft. and the wall of the model were 9 ft. tall you would multiply 9 in. by 2 ft. and get 18 ft.

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3 years ago

What is the domain of a function?

Gnom [1K]

The domain of a function is the set of all possible x-values which will make the function “work”, and will output real
y-values

4 0

3 years ago

Read 2 more answers

Ques no 1 b) help me!!!!! I will give you brainliest plzzz

saul85 [17]

Answer:

-4/5

Step-by-step explanation:

r=x/2

a=2x

ar²=-1/16

x^3=-1/8

x=-1/2

sn=a/1-r

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6 0

2 years ago

A line has a slope of 11 and passes through the point (2,4). PLSS HELPP I NEED IT

Ivenika [448]

Answer:

y = 11x - 18

Step-by-step explanation:

Use the equation y = mx + b

m (the slope) = 11

x (the x-coordinate) = 2

y (the y-coordinate) = 4

Plug it in for our original equation:

4 = 11*2 + b

4 = 22 + b

4 - 22 = b

b = -18

Therefore, the answer is y = 11x - 18. The tricks to these problems are usually in the same format, when you are given the slope and a point it passes through, just plug in the slope and the x and y, and solve for b. Hope this helps!

7 0

2 years ago

The owner of a bike shop that produces custom built bike frames has determined that the demand equation for bike frames is given

o-na [289]

Answer:

equilibrium point (10,340)

Step-by-step explanation:

To find the equilibrium point, equal the demand and the supply:

$D(q)=S(q)\\\\-6.10q^2-5q+1000=3.2q^2+10q-80$

Reorganize the terms in one side and reduce similar terms:

$3.2q^2+6.1q^2+5q+10q-80-1000=0\\\\9.3q^2+15q-1080=0$

that's a cuadratic equation, solve with the general formula when:

a=9.3, b=15, c=-1080

$q_{1}=\frac{-b+\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{1}=\frac{-15+\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{1}=\frac{-15+201}{18.6}\\\\q_{1}=\frac{186}{18.6}\\\\q_1=10$

q can't be negative because it is the quantity of bike frames, so:

$q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-15-\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{2}=\frac{-15-201}{18.6}\\\\q_{2}=\frac{-216}{18.6}\\\\$

This value of q can't be considered.

Then substitute the value of q in D(q) to find the price p:

$D(10) = -6.10(10)^2-5(10) + 1000\\\\D(10)=340=p$

The equilibrium point (q,p) is (10,340).

6 0

3 years ago