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3 years ago

Counting with combinations

Mathematics

1 answer:

Paladinen [302]3 years ago

7 0

Answer:

Step-by-step explanation:

35 divided by 5 equals 7

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find the radian measure of an angle at the center of a circle with radius 67.0 cm that intercepts an arc length of 118 cm

atroni [7]

Arc length = radius* angle
Solving for angle
---> angle = ArcLength/radius

$\theta = \frac{118}{67}$

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3 years ago

In the figure below, the segment is parallel to one side of the triangle. Find the value of x.

g100num [7]

Answer: x= . $18\frac{2}{3}$ .

Step-by-step explanation: We are given a segment parallel to the base.

Therefore, sides of big triangle and small triangles would be in proportion.

$\frac{One \ Side \ of\ big \ triangle }{One \ Side \ of\ small \ triangle} =\frac{Other \ Side \ of\ big \ triangle }{Other \ Side \ of\ small \ triangle}$

Setting values for the shown triangle, we get

$\frac{x+(x+7)}{x} =\frac{16+22}{22}$

$\frac{2x+7}{x} =\frac{38}{16}$

On cross multiplication, we get

16(2x+7) = 38(x)

32x + 112 = 38x.

Subtracting 112 from both sides, we get

32x + 112-112 = 38x -112

32x = 38x-112

Subtracting 38x from both sides, we get

32x-38x = 38x-38x-112

-6x = -112

Dividing both sides by -6, we get

$\frac{-6x}{-6} =\frac{-112}{-6}$

x= . $18\frac{2}{3}$ .

<h3>Therefore, x= . $18\frac{2}{3}$ .</h3>

7 0

3 years ago

How many degrees are inside of a convex 22-gon? <br> 1800<br> 1980<br> 1080<br> 3600

Brums [2.3K]

Answer:3600
Explanation:I’ve done this question before!

8 0

3 years ago

An object falls from a position of rest and

kumpel [21]

Answer:

About 4.1323 meters.

Step-by-step explanation:

We can use the following kinematic equations:

$\displaystyle v_f = v_0 + at \text{ and } \Delta d = v_0 t + \frac{1}{2} at^2$

We want to determine the distance the object has dropped after falling from rest and reaching an instantenous speed of 9 m/s.

We are given that the acceleration due to gravity is 9.8 m/s².

Using this fact and the first equation, find the time for which it took the object to reach 9 m/s. Note that the initial velocity is 0 m/s since the object started from rest.

$\displaystyle \begin{aligned} v_f = v_0 + at \\ \\ (9\text{ m/s}) & = (0\text{ m/s}) + (9.8\text{ m/s$^2$})t \\ \\ 9\text{ m/s} & = (9.8 \text{ m/s$^2$})t \\ \\ t &\approx0.9184 \text{ s} \end{aligned}$

To find how far the object dropped, we can use the second equation:

$\displaystyle\begin{aligned} \Delta d & = v_0 t + \frac{1}{2} at^2 \\ \\ & = (0\text{ m/s})(0.9184 \text{ s}) + \frac{1}{2}(9.8 \text{ m/s$^2$})(0.9184 \text{ s})^2 \\ \\ & = 4.1323 \text{ m} \end{aligned}$

In conclusion, the object would have dropped about 4.1323 meters.

6 0

3 years ago

Happy Monday Everybody<br><br><br> Free 100 points no joke

fgiga [73]

Answer: suppppp bro

Step-by-step explanation:

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3 years ago

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