Answer:
44. answer = a. (<)
45. answer = b. (>)
Step-by-step explanation:
To find the relation between the angles, we can use the law of sines in the triangle that contains both angles.
So for question 44, the angles mQRW and mRWQ are both in the triangle QWR, so we have:
10 / sin(mQRW) = 17 / sin(mRWQ)
sin(mQRW) / sin(mRWQ) = 10 / 17
The bigger the sine of the angle, the bigger the angle, so if the ratio between the sine of mQRW and sine of mRWQ is lesser than 1, the angle mQRW is lesser than the angle mRWQ (correct option: a.)
In the same way, in the question 45, the angles mRTW and mTWR are both in the triangle TWR, so we have:
15 / sin(mRTW) = 8 / sin(mTWR)
sin(mRTW) / sin(mTWR) = 15 / 8
If the ratio between the sine of mRTW and sine of mTWR is greater than 1, the angle mRTW is greater than the angle mTWR (correct option: b.)
Basically, the angle opposite to the greater side is the greater angle, and the angle opposite to the smaller side is the smaller angle.
