Answer: AA similarity theorem.
Step-by-step explanation:
Given : AB ∥ DE
Prove: ΔACB ≈ ΔDCE
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
Also ∠C ≅ ∠C using the reflexive property.
Therefore by AA similarity theorem , ΔACB ≈ ΔDCE
- AA similarity theorem says that if in two triangles the two pairs of corresponding angles are congruent then the triangles are similar .
6x = 4y - 8
4y = 6x + 8
y = (3/2) x + 2
Answer: Slope 3/2, y intercept 2
First you grapgh 0,-3 then you follow the slope of going 4 up 5 to the right and contine up also on e-where it is 0,-3 you go down 4 and 5 to the left and contine that to make a straught line.
I think it is B because it isn’t a solid line and it’s going up
Answer:
Step-by-step explanation:
<u>We know that</u>
- The diagonals of a rectangle are of equal length
- The diagonals bisect each other
<u>Considering the above we have:</u>
<u>Substitute the given values and solve for x:</u>
- 24x - 8 = 2*(8x + 4)
- 24x - 8 = 16x + 8
- 24x - 16x = 8 + 8
- 8x = 16
- x = 16/2
- x = 2
