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3 years ago

Mg + 2HCl → MgCl2 + H2 1. Is the equation above balanced? How do you know?

Chemistry

2 answers:

slega [8]3 years ago

4 0

<h2>Yes it is balanced as number of atoms of each element has to be same on reactant and product side</h2>

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$Mg+2HCl\rightarrow MgCl_2+H_2$

Thus in the reactants, there are 2 atoms of hydrogen , 2 atoms of chlorine and 1 atom of magnesium.

Thus there will be 2 atoms of hydrogen , 2 atoms of chlorine and 1 atom of magnesium in the product as well.

Thus the above equation is balanced

Learn more about law of conservation of mass

brainly.com/question/12335419

brainly.com/question/11954533

Tanzania [10]3 years ago

4 0

Answer:

Yes

Explanation:

If MG = 2HCl is blanced, that means MgCl2 = H2 is balanced.

So then its yes.

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Calculate the number of mg of Mn2+ left

soldi70 [24.7K]

Answer:

1.930 * 10⁻⁹ mg of Mn⁺² are left unprecipitated.

Explanation:

The reaction that takes place is:

Mn⁺² + S⁻² ⇄ MnS(s)

ksp = [Mn⁺²] [S⁻²]

If the pksp of MnS is 13.500, then the ksp is:

$ksp=10^{-13.500}=3.1623*10^{-14}$

From the problem we know that [S⁻²] = 0.0900 M

We use the ksp to calculate [Mn⁺²]:

3.1623*10⁻¹⁴= [Mn⁺²] * 0.0900 M

[Mn⁺²] = 3.514 * 10⁻¹³ M.

Now we can calculate the mass of Mn⁺², using the volume, concentration and atomic weight. Thus the mass of Mn⁺² left unprecipitated is:

3.514 * 10⁻¹³ M * 0.1 L * 54.94 g/mol = 1.930 * 10⁻¹² g = 1.930 * 10⁻⁹ mg.

6 0

3 years ago

What does an atom contain?

netineya [11]

Answer:

neutron, proton, and electrons

Explanation:

The protons and the neutrons make up the center of an atom which is called the nucleus

7 0

3 years ago

Your lab partner combined chloroform and acetone to create a solution where the mole fraction of chloroform, Xchloroform, is 0.1

jeyben [28]

Answer:

Explanation:

[u]Assumptions[/u]

1. There is exactly 1 mole of chloroform

2. The liquids mix together well such that the volume of the solution is the sum of the volumes of the two liquids

Given that the mole fraction of the Chloroform is 0.171

Mole fraction of Chloroform =

Mole of chloroform /(Mole of chloroform + mole of acetone)

According to assumptions, mole of chloroform is equal to 1

Therefore 0.171 =1/(1+mole of acetone)

1 + mole of acetone = 1/0.171

Mole of acetone = 1(/0.171) - 1

Moles of acetone = 4.85mol.

From Stochiometry

Mass of acetone = Mole of acetone * Molar Mass of acetone

Molar mass of acetone = 58.1grams/mol

Mass of acetone = 4.85 *58.1 = 282g =0.282kg

Mass of chloroform = moles of chloroform *Molar mass of Chloroform

Molar mass of chloform = 119.4 grams/mol

Mass of chloroform = 1* 119.4 =119.4g=0.1994kg

Volume of acetone = Mass of acetone / Density of acetone

Volume of acetone = 282/0.791

Volume of acetone = 357mL

Volume of Chloroform = Mass of Chloroform /Density of Chloroform

Volume of Chloroform = 119.4/1.48

= 81mL

Total volume of solution = 357mL+81mL = 438mL = 0.438L

1. Molarity = Moles of solute(chloroform)/mass of solvent (acetone) in kg

Molarity = 1/0.282 = 3.55molal

2. Molarity = moles of solute( chloroform) /Volume of solution

= 1/0.438 =2.28Molar

Therefore the molality and molarity respectively are 3.55 and 2.28.

4 0

4 years ago

*<br> Se pueden añadir números en cualquier lugar de la ecuación

algol [13]

Answer:

ukinam

Explanation:

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8 0

3 years ago

The air inside a flexible 3.5L container has a pressure of 115Kpa. What should the volume of the container be increased to in th

LenaWriter [7]

Answer:

V₂ = 4.82 L

Explanation:

Given data:

Initial volume of gas = 3.5 L

Initial pressure = 115 Kpa

Final volume = ?

Final Pressure = 625 torr

Solution:

Final Pressure = 625 torr (625/760 =0.82 atm)

Initial pressure = 115 Kpa (115/101 = 1.13 atm)

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.13 atm × 3.5 L = 0.82 atm × V₂

V₂ = 3.955 atm. L/0.82 atm

V₂ = 4.82 L

5 0

4 years ago