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monitta
3 years ago
11

How many particles are in 8.00 moles of bromine?

Chemistry
2 answers:
tester [92]3 years ago
7 0

Answer:

639.232 grams

Explanation:

Jet001 [13]3 years ago
4 0

Answer: 4.816 x 10^24 Particles

Explanation: 1mole of any substance contains 6.02x10^23 Particles

Therefore, 8 moles of bromine will contain = 8 x 6.02x10^23 = 4.816 x 10^24 Particles

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The frequency light of 3.52*10-7
zimovet [89]

Answer:

The speed of light, c, equals the wavelength, λ (pronounced lambda), times the frequency, ν, (pronounced noo).

c=λν

c is a constant. It is usually given as 3.00×108 m/s or 3.00×1010 cm/s rounded to three significant figures.❤

7 0
3 years ago
A covalent chemical bond is one in which
vitfil [10]
I think the answer is c
4 0
3 years ago
9. According to an "alternative theory", H2O is
Jlenok [28]

Answer:(4) ----accepts  a proton

Explanation:

H2O water can produce both hydrogen and   hydroxide ions

H2O --> H+ + OH-

According to the Bronsted-Lowry theory, it can be a proton donor and a proton acceptor.this means that It can donate a hydrogen ion to become its conjugate base, or  can accept a hydrogen ion to form its conjugate acid,

When , a water molecule, H2O accepts a proton it will act as a Brønsted-Lowry base especially when dissolved in a strong acidic medium. for eg

HCl + H2O(l) → H3O+(aq) + Cl−(aq)

Here, Hydrochloric acid is a strong acid and ionizes completely in  water, since it is more acidic than water, the water will act as a base.

6 0
3 years ago
The graph given below shows the motion of four runners P, Q, R, and S in a 5 km marathon.
wel

Answer:-

As we can see from the graphical data,

The distance covered by all the four runners is the same 5 km.

Among the four athletes, Athlete P covers the distance in under three hours.

It is the minimum time taken among the four athletes.

Thus Athlete P covers the 5 km distance in the minimum amount of time.

We know that speed = \frac{Distance}{Time}

Since time taken for P is minimum, his speed is the maximum. P ran the fastest.

Time taken by Q = 4.5 hours.

Speed of Q = \frac{Distance}{Time taken by Q}

                     = \frac{5km}{4.5hour}

                    = 1.1 km/ hr

Time taken by R = 6 hours.

Speed of R = \frac{Distance}{Time taken by R}

                     = \frac{5km}{6hour}

                    = 0.8 km/ hr

3 0
3 years ago
9.05 mol of oxygen gas to g of oxygen gas
NARA [144]
Molar mass of oxygen gas:

O₂ = 16 * 2 = 32.0 g/mol

1 mole O₂ -------------- 32.0
9.05 mole O₂ ---------- ?

Mass = 9.05 * 32.0

Mass = 289.6 g of O₂

hope this helps!
7 0
3 years ago
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