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Virty [35]
2 years ago
5

A Group 2 metal with an electron configuration of [Ne]3s2 combines with fluorine (F2) to

Chemistry
1 answer:
lidiya [134]2 years ago
3 0

The molar mass of the product is equal to 62g/mol.

<h3>Mole calculation</h3>

To calculate the molar mass of a compound it is necessary to have knowledge of the atomic mass of all the elements involved.

In the case of the question, we have the reaction between flourine and magnesium, which represents the element of group 2 with the presented electronic configuration.

Thus, we have the following reaction:

                                   Mg^{+2} + 2F^{-1} = MgF_2

So, just add the molar masses, having:

MM_Mg = 24.3g/mol\\MM_F = 19g/mol

                                               24.3 + 19 + 19 = 62.3g

So, the molar mass of the product, round to the nearest tenth, is equal to 62g/mol.

Learn more about mole calculation in: brainly.com/question/2845237

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A stock solution is a solution of a known concentration. Stock solution has a high concentration and therefore, the known amount of stock solution is used for preparing different concentrations, by diluting the same with the known amount of the solvent being used, such as water. 
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3 years ago
Which of the following are not single-displacement reactions?
Goshia [24]

Answer:

\boxed{\text{B and C }}

Explanation:

In a single-displacement reaction, one element exchanges partners with another element in a compound.

\textbf{A. } \rm Fe + 2HCl \longrightarrow FeCl_2 + H_2

This is a single-displacement reaction, because the element Fe exchanges partners with H in HCl.

\textbf{B. } \rm KOH + HNO_3 \longrightarrow H_2O + KNO_3

This is not a single-displacement reaction, because it is a reaction between two compounds.

This is a double displacement reaction in which the K⁺ and H⁺ cations change partners with the anions.

\textbf{C. } \rm Na_2S + 2HCl \longrightarrow 2NaCl + H_2S

This is not a single-displacement reaction. It is another double displacement reaction, in which the Na⁺ and H⁺ cations change partners with the anions.

\textbf{D. } \rm Ca + 2HOH \longrightarrow Ca(OH)_2 + H_2

This is a single-displacement reaction, because the element Ca exchanges partners with H in H₂O.

\boxed{\textbf{B and C }} are not single-displacement reactions.

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3 years ago
How to make a sugar cube dissolve more quickly in water?
Vesna [10]
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Which of the following are correct for zero-order reactions?
GREYUIT [131]

Answer:

The answer is "Choice A and Choice B"

Explanation:

The Zero-Order reactions are usually found if a substrate, like a surface or even a catalyst, is penetrated also by reactants. Its success rate doesn't depend mostly on the amounts of the various reaction in this reaction.

Let the Rate = k

As \frac{dx}{dt} \ rate\ \  K_0 doesn't depend on reaction rate, a higher reaction rate does not intensify the reaction.

By the rate k_0 =\frac{dx}{dt}, the created based and the reaction rate is about the same.

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What happens if you mix any halogen with any alkali?
kow [346]

Answer:

if you mix any halogen with any alkali then ionic salt will be formed and also this will cause an exothermic reaction in which heat is getting released

8 0
3 years ago
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