Question

A​ sparkling-water distributor wants to make up 200 gal of sparkling water to sell for $ 5.00 per gallon. She wishes to mix three grades of water selling for ​$10​.00, ​$1​.00, and​ $4.50 per​ gallon, respectively. She must use twice as much of the​ $4.50 water as the $ 1.00 comma water. How many gallons of each should she​ use?

Answer 1

The answer will be D

Answer 2

Answer:

x=50

y=50

z=100

Step-by-step explanation:

Let x = $10

y = $1

z = $4.5

2y=z

5 * 200 = 1000 Dollars wanted

1000 = 10x + y + 4.5z

variables represent number of gallons of each type

1000 = 10x + y + 4.5(2y)      sub z for y

x=50

y=50

z=100