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ioda
4 years ago
5

Eliminating Fractions from Equations

Mathematics
1 answer:
garri49 [273]4 years ago
7 0

Answer:

12 is the best answer

I think

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Find four consecutive integers with the sum of 54
Maksim231197 [3]

54/4 = 13.5

 take the 2 whole numbers below 13.5 and the 2 whole numbers above 13.5

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maks197457 [2]

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3 years ago
Read 2 more answers
find the number of terms in an AP given that its first and last terms are 13 and - 23 respectively and that its common differenc
Leokris [45]

Answer:

<u>There are 17 terms in the sequence</u>

Step-by-step explanation:

<u>Arithmetic Sequence </u>

An arithmetic sequence is a list of numbers with a definite pattern by which each term is calculated by adding or subtracting a constant number called common difference to the previous term. If n is the number of the term, then:

a_n=a_1+(n-1)r

Where an is the nth term, a1 is the first term, and r is the common difference.

In the problem at hand, we are given the first term a1=13, the last term an=-23, and the common difference r=-2 1/4. Let's solve the equation for n:

\displaystyle n=1+\frac{a_n-a_1}{r}

We need to express r as an improper or proper fraction:

\displaystyle r=-2\frac{1}{4}=-2-\frac{1}{4}=-\frac{9}{4}

Substituting:

\displaystyle n=1+\frac{-23-13}{-\frac{9}{4}}

\displaystyle n=1+\frac{-36}{-\frac{9}{4}}

\displaystyle n=1+36*\frac{4}{9}=17

n=17

There are 17 terms in the sequence

5 0
3 years ago
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