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creativ13 [48]
3 years ago
11

2a+6b=100 what is 5a+15b=?

Mathematics
2 answers:
algol [13]3 years ago
8 0

Answer:

Step-by-step explanation:Simplifying

2a + 6b = 100

Solving

2a + 6b = 100

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-6b' to each side of the equation.

2a + 6b + -6b = 100 + -6b

Combine like terms: 6b + -6b = 0

2a + 0 = 100 + -6b

2a = 100 + -6b

Divide each side by '2'.

a = 50 + -3b

Simplifying

a = 50 + -3b

Damm [24]3 years ago
7 0

Answer:

5(50x - 3bx + 50 - a) or 5(a + 3b) (Depending on the question and what is asked)

Step-by-step explanation:

2a + 6b = 100

a = 50-3b

b = 50/3 - 1/3a

replace

5a + 15b =

5*50-3b + 15*50/3 - 1/3a =

5(50x - 3bx + 50 - a)

^This would be the answer if we use the same value of a and b from the 2a+6b=100 equation.

If we use a unknown value for a and b. Then, the answer would be 5(a + 3b).

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Answer:

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Step-by-step explanation:

multiply both sides by 15

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3 years ago
Yesterday, the snow was 2 feet deep in front of Archie’s house. Today, the snow depth dropped to 1.6 feet because the day is so
IgorLugansk [536]

Answer: The depth of the snow has changed .4 inches. This is because it has melted in the warm weather. You can find the difference, by subtracting 1.6 from 2.          

Step-by-step explanation:

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Hope it helps!!!!

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one x-intercept for a parabola is at the point (2, 0). use the quadratic formula to find the other x-intercept for the parabola
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Answer:

Step-by-step explanation:

There are 3 ways to find the other x intercept.

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2) Just solving for x when y = 0, by using the quadratic formula.

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So the other x - intercept is at (1, 0)

3) Using Vietta's Theorem regarding the solutions of a quadratic

Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.

x_1 + x_2 = \frac{-b}{a}

And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.

x_1 \cdot x_2 = \frac{c}{a}

These relations between the solutions give us a brief idea of what the solutions should be like.

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Step-by-step explanation:

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