Answer:
2 real solutions
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 ), then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct solutions
• If b² - 4ac = 0 then 2 real and equal solutions
• If b² - 4ac < 0 then no real solutions
x² + 4x - 3 = 0 ← is in standard form
with a = 1, b = 4, c = - 3 , then
b² - 4ac = 4² - (4× 1 × - 3) = 16 - (- 12) = 16 + 12 = 28
Since b² - 4ac > 0 then the equation has 2 real and distinct solutions
Answer:
Look down below!
Step-by-step explanation:
Fist, make your inequality:
-x + 5y > -10
5y > x - 10
y = .2x - 2
Now, plug in any value of x to find y!
Ex: x = 5...
y = .2 (5) - 2
y = -1
Your first coordinate could be (5, -1)
Hope this helps!
Answer:
13 and -14 satisfy this condition
Step-by-step explanation:
Let's represent that number as x
and the square of x is x^2
So,
x + x^2 = 182
Subtract 182 from both sides
x + x^2 - 182 = 182 - 182
x + x^2 - 182 = 0
rearrange the quadratic equation
x^2 + x -182 = 0
let's use the quadratic formula
or 
a = 1, b = 1, c = -182
or 
or 
or 
or 
or 
13 or - 14
Lets check
13 + 13^2 = 13 + 169
= 182
Also,
-14 + (-14^2) = -14 + 196
= 182
Answer:
A
Step-by-step explanation:
Since each triangle is an equilateral triangle all side are the same length. Thus, one side is 15/3=5 inches. The perimeter of the entire figure would then be 3x6=18 since there are 6 sides.
Isolate x by adding 8 to both sides.
3 = x/3
Then, multiply by 3 on both sides.
9 = x
To prove that this is right, you can imput 9 into the equation and it equals -5.
