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Len [333]
2 years ago
5

Give the set of four quantum numbers that could represent the last electron added (using the Aufbau principle) to the Cl atom.A)

n=3, l=1, ml=1ms=+12B) n=3, l=0, ml=1, ms=−12C) n=3, l=2, ml=1, ms=+12D) n=2, l=1, ml=1, ms=−12E) n=3, l=1, ml=1, ms=−12
Mathematics
1 answer:
leva [86]2 years ago
4 0

Answer:

n=3, l=1, ml=1ms=+1/2

Step-by-step explanation:

The electron configuration of chlorine atom is; [Ne] 3s² 3p⁵.

This means that the last electron is found in a 3pz orbital.

We can see that the principal quantum number is 3. The electron is in a p orbital so l=1, the electron must be found in a 3pz orbital hence ml=1. The electron is found alone in that orbital hence s= 1/2.

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14 kg of apples cost $154.how much would 16kg cost
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The data set represents the total number of people who bought bananas each hour at a grocery store.
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Pls help me on this question :-
Nastasia [14]

Answer:

We conclude that the rule for the table in terms of x and y is:

  • y = 3x+2

Step-by-step explanation:

The table indicates that there is constant change in the x and y values, meaning the table represents the linear function the graph of which would be a straight line.

We know the slope-intercept form of the line equation

y = mx+b

where m is the slope and b is the y-intercept.

Taking two points

  • (-2, -4)
  • (-1, -1)

Finding the slope between (-2, -4) and (-1, -1)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-2,\:-4\right),\:\left(x_2,\:y_2\right)=\left(-1,\:-1\right)

m=\frac{-1-\left(-4\right)}{-1-\left(-2\right)}

m=3

We know that the y-intercept can be determined by setting x = 0 and finding the corresponding y-value.

Taking another point (0, 2) from the table.

It means at x = 0, y = 2.

Thus, the y-intercept b = 2

Using the slope-intercept form of the linear line function

y = mx+b

substituting m = 3 and b = 2

y = 3x+2

Therefore, we conclude that the rule for the table in terms of x and y is:

  • y = 3x+2
7 0
3 years ago
Which classification describes AMNO with vertices M(2, -3), N(3, 1), and<br> 0(-3, 1)?
Sonja [21]

Answer:

Option D

Step-by-step explanation:

32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).

Distance between two points (x_1,y_1) and (x_2,y_2) is given by the expression,

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between M(2, -3) and N(3, 1) will be,

MN = \sqrt{(3-2)^2+(1+3)^2}

      = \sqrt{1+16}

      = \sqrt{17}

Distance between M(2, -3) and O(-3, 1),

MO = \sqrt{(2+3)^2+(-3-1)^2}

      = \sqrt{25+16}

      = \sqrt{41}

Distance between N(3, 1) and O(-3, 1),

NO = \sqrt{(3+3)^2+(1-1)^2}

      = 6

Condition for right triangle,

c² = a² + b² [Here c is the longest side of the triangle]

By this property,

MO² = MN² + NO²

(\sqrt{41})^2=(\sqrt{17})^2+6^2

41 = 17 + 36

41 = 51

False.

Therefore, given triangle is not a right triangle.

Since, length of all sides are not equal, given triangle will be a scalene triangle.

Option D is the correct option.

5 0
3 years ago
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