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maw [93]
3 years ago
6

Millie truncates the number N to 1 digit the result is 8 write down the error interval

Mathematics
1 answer:
juin [17]3 years ago
5 0

Answer:

Interval for N ⇒ 8 ≤ N < 9

The interval error is ⇒ 0 ≤ <u>error </u>< 1

Step-by-step explanation:

Truncate a number means  we find an estimate for the number without doing any rounding.

To truncate a number to 1 digit, miss off all the digits after the decimal point.

So, for the giving problem:

Truncates the number N to 1 digit the result is 8 write down the error interval

So, the number will between 8 and 9

So, the interval for N ⇒ 8 ≤ N < 9

And the interval error (e) is ⇒ 0 ≤ e < 1

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Answer:

The identity property

Step-by-step explanation:

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3 years ago
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
9:18 in the lowest term
skelet666 [1.2K]
9/18 in lowest term is 1/2

Work:

9/18 ÷ 9/9 = 1/2

1/2 = 0.5

0.5 = 50%
6 0
3 years ago
Read 2 more answers
n ΔABC, if the length of sides a, b, and c are 3.5 centimeters, 5.5 centimeters, and 6 centimeters respectively, what is m∠C to
borishaifa [10]
We are given with three sides with measurements such as below:
a = 3.5 cm 
b = 5.5 cm
c = 6 cm
We are asked to solve for m∠C. To solve this we need to apply Law of Cosines such as below:
cos C = a²+b² - c² /2ab
cos C = 3.5² + 5.5² -6² / (2*3.5*5.5)
cos C = 0.16883
C = 80.28°
7 0
3 years ago
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