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Lapatulllka [165]
3 years ago
10

I need help with this I don't get it at all

Mathematics
2 answers:
iren [92.7K]3 years ago
8 0

Answer:

the answer is C

Step-by-step explanation:

because the negative needs to be on the inside not on the outside

enyata [817]3 years ago
8 0

Answer:

D

Step-by-step explanation:

you cant get the answer if the number is negative

since it's a square it's either positive or 0(zero)

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Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A
Vlad [161]

Answer:

y(x)=sin(2x)+2cos(2x)

Step-by-step explanation:

y''+4y=0

This is a homogeneous linear equation. So, assume a solution will be proportional to:

e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda

Now, substitute y(x)=e^{\lambda x} into the differential equation:

\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0

Using the characteristic equation:

\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0

Factor out e^{\lambda x}

e^{\lambda x}(\lambda ^2 +4) =0

Where:

e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda

Therefore the zeros must come from the polynomial:

\lambda^2+4 =0

Solving for \lambda:

\lambda =\pm2i

These roots give the next solutions:

y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}

Where c_1 and c_2 are arbitrary constants. Now, the general solution is the sum of the previous solutions:

y(x)=c_1 e^{2ix} +c_2 e^{-2ix}

Using Euler's identity:

e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)

y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\

Redefine:

i(c_1-c_2)=c_1\\\\c_1+c_2=c_2

Since these are arbitrary constants

y(x)=c_1sin(2x)+c_2cos(2x)

Now, let's find its derivative in order to find c_1 and c_2

y'(x)=2c_1 cos(2x)-2c_2sin(2x)

Evaluating    y(0)=2 :

y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2

Evaluating     y'(0)=2 :

y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1

Finally, the solution is given by:

y(x)=sin(2x)+2cos(2x)

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3 years ago
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Step-by-step explanation:

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An example of dependent events is drawing a green marble out of one jar and then drawing a....?
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Dependent events involve a first event that affects the outcome of a second event. This means that the probability for the second event has changed because of the occurrence of the first event. This is usually present in probabilities without replacement because each event has a different condition. The answer is <span>C)red marble out of the same jar,without replacing the first marble.</span>
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Please answer this question!
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The answer is D, 2,500
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In the given figure PQ is a transversal intersecting lines AB and CD. Find the measures of angles x and y. Hence prove AB//CD.​
tekilochka [14]

<u>Explanation</u><u>:</u>

From the given figure ,

AB || CD

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⇛ x = 180°-50°

⇛ x = 130°

Therefore, "x" = 130°

and

130° and y are vertically opposite angles which are equal.

⇛ "y" = 130°

Therefore, y = 130°

<u>Additional</u><u> </u><u>comment</u><u>:</u><u>-</u>

  1. If two parallel lines Intersected by a transversal then
  2. Corresponding angles are equal.
  3. Vertically Opposite angles are equal.
  4. The sum of two adjacent angles is equal to 180° then they are called Linear Pair.

3 0
2 years ago
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