Ask question

Ask question

All categories

3 years ago

5

If the ice cube is left out for 2 hours , but put back into the freezer will it still have its same shape/size ?

1 answer:

zubka84 [21]3 years ago

4 0

Yes it's size and shape will change when we will keep it in the freezer again

You might be interested in

Eva took a taxi from her house to the airport. The taxi company charged a pic of feet of 3 dollars and 20 cents, plus 3 dollars

svetoff [14.1K]

Answer:

3x + 3.20 =33.20

Step-by-step explanation:

4 0

2 years ago

Area of a regular hexagon with an apothem of 15 cm

Anton [14]

Answer:

area = 779.4 cm²

Step-by-step explanation:

divide it into 6 equal equilateral triangles. Each corner of a triangle will be 60°.

tan 60° = 15/x

1.7321 = 15/x

x = 8.66 (this is one-half of the base of the triangle)

base = 17.32 cm

area of one triangle = 1/2(17.32)(15) = 129.9 cm²

129.9(6) = 779.4 cm² (because 6 triangles make up the hexagon)

8 0

2 years ago

Hey Bestie! 50 pts Pls help! Real answers only pls <3

frosja888 [35]

Answer:

$1. \: 3i$

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2> $1. \: \sqrt{ - 9}$ </h2>

$\sqrt{ - 1(9)}$

$\sqrt{ - 1} \times \sqrt{ 9}$

$i \times \sqrt{9}$

$i \times \sqrt{ {3}^{2} }$

$i \times 3$

$3i$

<h2> $2. \: \sqrt{ - 8}$ </h2>

$\sqrt{ - 1(8)}$

$\sqrt{ - 1} \times \sqrt{8}$

$i \times \sqrt{8}$

$i \times \sqrt{ {2}^{2} \times 2 }$

$2i \sqrt{2}$

<h2> $3. \: \sqrt{ - 80}$ </h2>

$\sqrt{ - 1} \times \sqrt{80}$

$i \times \sqrt{80}$

$4i \: \sqrt{5}$

<h2> $4. \: \sqrt{ - 75}$ </h2>

$\sqrt{ - 1} \times \sqrt{75}$

$i \times \sqrt{75}$

$i \times \sqrt{ {5}^{2} \times 3 }$

$5i \sqrt{3}$

<h2> $5. \: \sqrt{ - 72}$ </h2>

$\sqrt{ - 1} \times \sqrt{72}$

$i \times \sqrt{72}$

$i \times ( {6}^{2} \times 2)$

$6i \sqrt{2}$

<h2> $6. \sqrt{ - 20}$ </h2>

$\sqrt{ - 1} \times \sqrt{20}$

$i \times \sqrt{20}$

$i \times \sqrt{ {2}^{2} \times 5}$

$2i \sqrt{5}$

<h2> $7. \: \sqrt{ - 27}$ </h2>

$\sqrt{ - 1} \times \sqrt{27}$

$i \times \sqrt{27}$

$i \times \sqrt{ {3}^{2} \times 3}$

$3i \sqrt{3}$

<h2> $8. \: \sqrt{ - 12}$ </h2>

$\sqrt{ - 1 \times 12}$

$i \times \sqrt{12}$

$i \times \sqrt{4(3)}$

$2i \sqrt{3}$

<h2> $9. \: \sqrt{ - 125}$ </h2>

$\sqrt{ - 1} \times \sqrt{125}$

$i \times \sqrt{ {5}^{2} \times 5 }$

$5i \sqrt{5}$

<h2> $10. \: \sqrt{ - 180}$ </h2>

$\sqrt{ - 1} \times \sqrt{180}$

$i \times \sqrt{ {6}^{2} \times 5 }$

$6i \sqrt{5}$

<h3>Hope it is helpful...</h3>

5 0

2 years ago

Evaluate the function.<br> f(x) = –x^2+ 3x + 13<br> Find f(-10)

oksian1 [2.3K]

Answer:

-117

Step-by-step explanation:

Plug -10 in every time you see "x". Then, I used a calculator to evaluate the function (find the answer). Then, I got -117.

Hope this helped :)

8 0

3 years ago

50 points! Look at the picture attached. I will mark brainliest

Radda [10]

I’m pretty sure the answer would be 116

8 0

2 years ago

Read 2 more answers