For two triangles to be congruent by AAS:
1- Two angles in the first triangle must be equal to two angles in the second triangle
2- A non included side in the first triangle is equal to a non included side in the second triangle
Now, let's check our options. We will find that:
For the two triangles UTV and ABC:
angle T = angle A
angle V = angle C
TU (non-included between angles T & V) = AB (non-included between angles A & C)
Therefore, we can conclude that:
Triangles ABC and UTV are congruent by AAS
825 meters away
i think bit too sure
You just Said it it's 0,6666666666...
I'm not sure what side is missing but you could use the proportions
A/B=X/Y or B/C=Y/Z or CA/=ZX. it also works if you reverse this for example B/A=Y/X
Here ya go. I hope this helps! :) (It was much easier to do this than to try and type it out, in my opinion)