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musickatia [10]
3 years ago
9

What are the qualification of? 0.3%

Mathematics
1 answer:
KIM [24]3 years ago
4 0

Answer:

30

Step-by-step explanation:

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Simplify<br>( 2 4/5 * 1 3/10) * 1 1/2 ​
Rashid [163]

Answer:

( 2 4/5 * 1 3/10) * 1 1/2 = 5 23/50

Step-by-step explanation:

( 2 4/5 * 1 3/10) * 1 1/2 = 14/5 x 13/10 x 3/2 = 546/100 = 5 46/100 = 5 23/50

4 0
3 years ago
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How to round o.175 thousands
Sliva [168]
It has a bunch of zeroes after the five so it is rounded unless you want to go to .18
4 0
4 years ago
1/2+2/3 divided by 1/6
pentagon [3]

Answer:

4 1/2

Step-by-step explanation:

Just do the math work it out on paper and check it!

3 0
2 years ago
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Someone help meh and tell me how u did it
morpeh [17]

Answer: 2 4/9

The decimal equivalent is 2.44

Step-by-step explanation:

It may help to convert the fractions to decimals. Divide the numerator by the denominator.

2 3/8 is 2.375

2 1/8 is 2.125 etc.

Remember that absolute value is considered positive. Then put the numbers in order.

7 0
3 years ago
Read 2 more answers
1. cot x sec4x = cot x + 2 tan x + tan3x
Mars2501 [29]
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
    cot(x)sec⁴(x)            cot(x)sec⁴(x)
                   0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
                   0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
                   0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
                   0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
                   0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
                   0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
                   0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
                   0 = cos⁴(x)(1 + tan²(x))²
                   0 = cos⁴(x)        or         0 = (1 + tan²(x))²
                ⁴√0 = ⁴√cos⁴(x)      or      √0 = (√1 + tan²(x))²
                   0 = cos(x)         or         0 = 1 + tan²(x)
         cos⁻¹(0) = cos⁻¹(cos(x))    or   -1 = tan²(x)
                 90 = x           or            √-1 = √tan²(x)
                                                         i = tan(x)
                                                      (No Solution)

2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
              sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
   sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
                               sin²(x) - cos²(x) = sin²(x) - cos²(x)
                                         + cos²(x)              + cos²(x)
                                             sin²(x) = sin²(x)
                                           - sin²(x)  - sin²(x)
                                                     0 = 0

3. 1 + sec²(x)sin²(x) = sec²(x)
           sec²(x)             sec²(x)
      cos²(x) + sin²(x) = 1
                    cos²(x) = 1 - sin²(x)
                  √cos²(x) = √(1 - sin²(x))
                     cos(x) = √(1 - sin²(x))
               cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
                                 x = 0

4. -tan²(x) + sec²(x) = 1
               -1               -1
      tan²(x) - sec²(x) = -1
                    tan²(x) = -1 + sec²
                  √tan²(x) = √(-1 + sec²(x))
                     tan(x) = √(-1 + sec²(x))
            tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
                             x = 0
5 0
3 years ago
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