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3 years ago

How do I write the area of a rectangle as a product?

Mathematics

2 answers:

Mrac [35]3 years ago

5 0

The area of a rectangle equals Length times Width: L*W = A

Anastaziya [24]3 years ago

3 0

Area of a rectangle = width * length

<span>Replace them for the actual values, and you shall find the area of a rectangle. </span>

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Please help and show your work ( no links or files) plz

mr_godi [17]

Answer:

Step-by-step explanation:

Use the formula for the area of a triangle,

Area of a triangle = $\frac{1}{2}(\text{Base})(\text{Height})$

7). Area of the triangle = $\frac{1}{2}(20)(7.4)$

= 74 km²

8). Area of the triangle = $\frac{1}{2}(4)(15.4)$

= 30.8 cm²

9). Area of the triangle = $\frac{1}{2}(16)(7)$

= 56 m²

10). Area of the triangle = $\frac{1}{2}(11)(7.7)$

= 42.35 km²

5 0

2 years ago

Simplify:<br> = (answer here) ^a0

kari74 [83]

Answer:

Step-by-step explanation:

1) Using n√a^m = (n√a)^m, rewrite the root like (3√27)^2

2) Write the number in exponential form with a base of 3: (3√3^3)^2

3) Calculate the cube root: 3^2

4) Evaluate the power: 3^2=9

7 0

2 years ago

A baby is weighed on a defective scale. He weighed 28 pounds according to the scale. He weighs 25 pounds on an effective scale.

Anettt [7]

Answer:

Step-by-step explanation:

Step one:

given

expected weight= 28pounds

Actual weight= 25 pound

Required:

percent error

$\delta = \left| \frac{v_A - v_E}{v_E} \right| \cdot 100\%$

δ= percent error

vA =actual value observed

vE =expected value

δ=25-28/28*100

δ=-3/28*100

δ=0.107*100

δ=10.7%

The percent error is 10.7%

3 0

3 years ago

What is the solution to 5/6x-1/3 is greater than 1 1/3

VARVARA [1.3K]

Answer:

The solution of the expression is $x>2$

Step-by-step explanation:

Given : Expression $\dfrac{5}{6}x-\dfrac{1}{3}$ is greater than $1 \dfrac{1}{3}$

To find : The solution of teh expression ?

Solution :

According to question,

$\dfrac{5}{6}x-\dfrac{1}{3}>1 \dfrac{1}{3}$

$\dfrac{5}{6}x-\dfrac{1}{3}>\dfrac{4}{3}$

Adding $\frac{1}{3}$ both side,

$\dfrac{5}{6}x-\dfrac{1}{3}+\dfrac{1}{3}>\dfrac{4}{3}+\dfrac{1}{3}$

$\dfrac{5}{6}x>\dfrac{5}{3}$

Multiply $\frac{6}{5}$ both side,

$\dfrac{5}{6}x\times \frac{6}{5}>\dfrac{5}{3}\times\frac{6}{5}$

$x>2$

Therefore, The solution of the expression is $x>2$

7 0

2 years ago

Read 2 more answers

What is answer to 3 divided by eleven twelveths

ryzh [129]

Answer:

Step-by-step explanation:

The answer is 3.27

4 0

3 years ago