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Mazyrski [523]
3 years ago
15

MARKIN BRAINIEST !!!

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

B-1, C-2, A-3

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(y+6)(y - 4) = 0<br>0 prperty <br>​
Alex_Xolod [135]

Answer:

y = 4,-6

Step-by-step explanation:

0 property states that 0 times any number is 0

applying that here, that means y+6 = 0 or y-4 = 0

0(y-4) = 0; (y+6)(0) = 0

y+ 6 = 0

y = -6

y-4 = 0

y = 4

5 0
3 years ago
Solve the inequality 5(2x + 1) &lt; 10.<br> х&lt; 1/2<br> x&gt; 1/2<br> х&lt; 3/2<br> x&gt; 3/2
Maurinko [17]

Answer:

x < 1/2

Step-by-step explanation:

5(2x + 1) < 10

Divide each side by 5

5/5(2x + 1) < 10/5

2x+1 < 2

Subtract 1 from each side

2x+1-1 < 2-1

2x <1

Divide each side by 2

2x/2 <1/2

x < 1/2

4 0
2 years ago
Read 2 more answers
If Layla gets paid $948 a slow week . The employees Marco gets paid $9 an hour ,Stephanie gets paid $10.50 an hour ,and Destiny
deff fn [24]

Answer:

they all got paid 474$ all together

Step-by-step explanation:

destiny worked 12 hours and made 240.17$

Stephanie worked 12 hours and made 126.17$

Marco worked 12 hours and made 108.17$

this all adds up to 474.50$ which is exactly half of 949$

5 0
3 years ago
3x² + 2x + 2 + 4x2 + 5 simplify​
Y_Kistochka [10]

Answer:

3x^2+2x+15

Step-by-step explanation:

3x^2+2x+2+(4x2)+5

use pemdas

6 0
3 years ago
Read 2 more answers
Suppose that there are 15 antennas in a store, of which 3 are defective. Assume all the defectives and all the functional antenn
ohaa [14]

Answer:

Step-by-step explanation:

Total number of antenna is 15

Defective antenna is 3

The functional antenna is 15-3=12.

Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.

So,

We line up the 13 good ones, and see where the bad one will fits in

__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __

Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.

Then,

There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement

ⁿCr= n!/(n-r)!r!

The number of arrangement is

14C3=14!/(14-3)!3!

14C3=14×13×12×11!/11!×3×2

14C3=14×13×12/6

14C3=364ways

7 0
3 years ago
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