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storchak [24]
3 years ago
8

Expand & simplify 6(g + 4) + 5(8+3) +4

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

Answer: 6 g + 83

Step-by-step explanation: That is how far it can go.

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Select the correct product.
pshichka [43]
To find the answer of this problem, we need to distibute and multiply all of the numbers with each other.

2x * x + 2x * 1 + 9 * x + 9 * 1
= 2x^2 + 2x + 9x + 9
= 2x^2 + 11x + 9

The answer would be the first option.

Hope this helps!
6 0
2 years ago
Question 1 of 10
trapecia [35]

Answer:

D

Step-by-step explanation:

There are 4 queens out of 52 cards in a deck. Therefore, if each card has the same probability of getting chosen, you have a 4/52 = 0.077 chance of drawing a queen because there are (4 favorable outcomes/queens) / (52 total outcomes)

5 0
1 year ago
What is the amplitude of the function?
Licemer1 [7]

Answer:

2

Step-by-step explanation:

Take the absolute value of the lowest y value.

So

| - 1|  = 1

Take the absolute value of highest y value.

|3|  = 3

Add those two together and divide by two.

\frac{1 + 3}{2}  = 2

So the amplitude is 2

5 0
2 years ago
Summarize the rules for multiplying powers with the same base dividing powers with the same base raising a product to a power an
Mashcka [7]
The rules for multiplying powers with the same base is you are basically doing the pemdas method Please Excuse My Dear Aunt Sally pemdas
3 0
3 years ago
6) A standard deck has 52 cards, and contains 13 cards of each of the four suits: diamonds, spades, hearts, and clubs. What is t
Crazy boy [7]

Answer:

\dfrac{12}{51}\cong\dfrac{4}{17}

Step-by-step explanation:

You have 52 cards in a deck and 13 cards of each suit.

The probability of picking a diamond in a complete deck of cards is:

\dfrac {13}{52}

Or the probability is 13 put of 52.

Since you took out 1 diamond card already there would be only 51 cards left and 12 diamond cards left. So you would have a probability of:

\dfrac{12}{51}

If we simplify it you will have a probability of:

\dfrac{4}{17}

6 0
2 years ago
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