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2 years ago

How many cups equal 2 liters

Mathematics

2 answers:

FrozenT [24]2 years ago

5 0

Answer:

9 cups rounded

if not then 8.45351

Step-by-step explanation:

slava [35]2 years ago

4 0

Answer:

8.45351 equal two liters.

Step-by-step explanation:

You might be interested in

How many solutions does the equation -9(x+6)=-9x+108 have?

elixir [45]

Answer:

No solution

Step-by-step explanation:

Simplify the equation to solve for x.

-9(x+6)=-9x+108 Distribute

-9x-54=-9x+108 Combine like terms

+9x +9x

0-54=108 Combine like terms

+54 +54

0=162 No solution

4 0

3 years ago

A formula for finding P, the perimeter of a rectangle, is P = 2l + 2w, where l is the length of the rectangle, and w is its widt

Varvara68 [4.7K]

Answer:

P=30cm

Step-by-step explanation:

So the formula there is to find the Perimeter of the rectangle, so we are going to use it!

Using Substitution:

$A=2L+2W\\A=2(10)+2(5)\\A=20+10\\A=30$

Hope this helps!

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4 0

3 years ago

PLEASE HELP ME! TIMED!

erica [24]

Answer:

1.6-5 2. 42 3. 36/66

Step-by-step explanation:

6 0

2 years ago

Psychologist Michael Cunningham conducted a survey of university women to see whether, upon graduation, they would prefer to mar

bagirrra123 [75]

Answer:

A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.

B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.

C. The expected value of X is 6.75, and the standard deviation of X is 2.17.

Step-by-step explanation:

The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.

With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{25}{k} 0.25^{k} 0.75^{25-k}\\\\\\$

A. P(x=6)

$P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.00024*0.00423=0.183\\\\\\$

B. P(x≥10)

$P(x\geq10)=1-P(x$

$P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0.0008=0.0008\\\\\\P(x=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.25*0.001=0.0063\\\\\\P(x=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.0625*0.0013=0.0251\\\\\\P(x=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.0156*0.0018=0.0641\\\\\\P(x=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.0039*0.0024=0.1175\\\\\\P(x=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.001*0.0032=0.1645\\\\\\P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.0002*0.0042=0.1828\\\\\\$

$P(x=7) = \dbinom{25}{7} p^{7}(1-p)^{18}=480700*0.000061*0.005638=0.1654\\\\\\P(x=8) = \dbinom{25}{8} p^{8}(1-p)^{17}=1081575*0.000015*0.007517=0.1241\\\\\\P(x=9) = \dbinom{25}{9} p^{9}(1-p)^{16}=2042975*0.000004*0.010023=0.0781\\\\\\$