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svlad2 [7]
3 years ago
15

Please help it’s due tonight Math

Mathematics
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

m < 36

yes, Jamie is correct.

Step-by-step explanation:

I've bolded the statements that you can put down to show your work

the maximum that Jamie is willing to practice for the week is 300 minutes, so you can start by creating an inequality for that.

total minutes throughout the week < 300

next, you know that a week is monday through friday + the weekend, and the amount of minutes Jamie will practice for the weekend is already given.

so, you can rewrite the earlier inequality like so

Monday through Friday practice + 120 < 300

since Jamie plans to practice the same amount of time (m) for each day, and there are 5 days between monday and friday, you can substitute values in the equation

5m + 120 < 300

simplify

5m < 300 - 120

5m < 180

m < 36

since half an hour is 30 minutes, the answer is yes, Jamie's claim is correct.

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6x^2-4xy-15xy+10y^2 factor by grouping
PtichkaEL [24]
4 answers · Mathematics
Best Answer
We will need to split the middle term and use the grouping method. To do this multiply the coefficient of the first term (6) against the coefficient of the last term (10):

6 * 10 = 60
Factors of 60 = +-(1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60)

From the list of factors find two numbers that when added together give -19 and when multiplied together give 60. -15 and -4 added together give -19 and multiplied together give 60 so split the middle term by rewriting these values back into the expression:

6x^2 - 15xy - 4xy + 10y^2

Now use the grouping method, take out the highest common factor between the two sets of terms:

3x(2x - 5y) - 2y(2x - 5y)

Group the outside terms:

(3x - 2y)(2x - 5y)


Answers
6 = -3*-2
10 = 5*2
5*3+2*2=19
thus
(2y-3x)(5y-2x)
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