All categories

3 years ago

What does the expression "5n" represent?

Mathematics

1 answer:

Andre45 [30]3 years ago

4 0

Answer:

the product of 5 and a number

Step-by-step explanation:

$5n$ is really $5 * n$ .

In higher education math, the multiplication sign is not used. A number and a variable (or a equation in grouping symbols) would be just together next to each other. When it's like this, you would have to multiply the numbers.

Example:

$4n; n = 2\\4(2) = 4* 2 = 8$

You might be interested in

Help find the measure of the angle indicated!!!?

Alecsey [184]

Answer:

50°

Step-by-step explanation:

$m\angle RST = \frac{1}{2} \times (150\degree - 50\degree) \\\\m\angle RST = \frac{1}{2} \times 100\degree \\\\ \purple{ \bold{m\angle RST =50\degree}} \\\\$

8 0

3 years ago

Caroline baked 3 dozen oatmeal raisin cookies for the bake sale at school this is 1/4 the number of dozens of cookies she baked

anyanavicka [17]

144 is how much cookies she baked

7 0

3 years ago

Gino brings home one book from each of his 5 school subjects and places them side by side on a

const2013 [10]

Answer:

about 50

Step-by-step explanation:

that's all I can think of

4 0

3 years ago

2.Solve the system using substitution.

Lena [83]

2x+2y=38
y=x+3

First you would substitute the y for x+3
2x+2(x+3)=38

You would multiply the 2 by the x+3
2x+2x+6=38

Add the 2x and the 2x
4x+6=38

Subtract the 6 on both sides
4x=32

Divide the 4 on both sides
x=8

Now substitute the x in the second problum for 8
y=8+3

Add the 8 and the 3 to solve for y
y=11

Your answers
x=8
y=11
the correct answer would be A:(8,11)

3 0

3 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2