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coldgirl [10]
3 years ago
15

Pleasee help I'm really struggling ​

Mathematics
1 answer:
deff fn [24]3 years ago
5 0
The cost of Tulip and Roses are 1500LL and 2500LL respectively

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Natalie invested $1,200 in an account paying an interest rate of 6.4% compounded continuously. Assuming no deposits or withdrawa
Keith_Richards [23]

Answer:

FV=$3,445

Step-by-step explanation:

FV=PV(1+i)^n (FV: Future value, PV: Present value)

i=0.064

n=17

FV=1200(1+0.064)^17

FV=3444.9975

FV=$3445.00

8 0
3 years ago
John looked at his bank account and noticed that he had $2,029.90 in his account. All that he could remember is that he created
Over [174]

We will have that for the previous year, he had in the account:

m_{y6}=2029.90-\frac{2029.90\cdot6}{100}\Rightarrow m_{y6}=1908.106

For the year previous to that one, he had:

m_{y5}=1908.106-\frac{1908.106\cdot6}{100}\Rightarrow m_{y5}=1793.61964

For the previous year to that, he had:

m_{y4}=1793.61964-\frac{1793.61964\cdot6}{100}\Rightarrow m_{y4}=1686.002462

For the year previous to that one, he had:

m_{y3}=1686.002462-\frac{1686.002462\cdot6}{100}\Rightarrow m_{y3}=1584.842314

For the second year that the money was in the account, there was:

m_{y2}=1584.842314-\frac{1584.842314\cdot6}{100}\Rightarrow m_{y2}=1489.751775

And the orinial ammount of money that was in the account was:

m_{y1}=1489.751775-\frac{1489.751775\cdot6}{100}\Rightarrow m_{y1}=1400.366669

From this, we know that Jhon had originally $1400.37 in the bank account.

6 0
1 year ago
For the pair of similar solids, find the value of the variable.
serg [7]

Answer:

2cm..................

4 0
3 years ago
Read 2 more answers
Which statements apply to the ratio of rice and water? Select two options. The amount of rice is the dependent value. The amount
Snowcat [4.5K]

Answer:

The values cannot be labeled as dependent or independent since any amount can be selected for either.

3 0
4 years ago
Read 2 more answers
Help me ASAP PLEASE
tamaranim1 [39]

Answer:

Your(my) number is 40

Step-by-step explanation:

I. Given 80/something, + 13, * 5 = 75 when x is something

So [  \frac{80}{x} + 13 ]5 = 75

     [ \frac{400}{x} + 65] = 75

     \frac{400}{x} = 75 - 65

     \frac{400}{x}  = 10

     400 = 10x

        x = 40

II. Prove by replace 40 in x

    [(80/40) + 13]5 = 75

    [2 + 13] 5 = 75

    (15)5 = 75

        75 = 75 true

Ask me for anything.

5 0
3 years ago
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