For the answer to the question if t<span>here are 2.5 centimeters in an inch and if a paperclip is 1.5 inches long, how many centimeters long is the paperclip.
The answer to this question is the paperclip is </span> 3.81 cm long.
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When Q = {all perfect squares less than 30} and p={ all odd numbers from 1 to 10) Q ∩ P = { 1, 9}
<h3>How to calculate the value?</h3>
Set theory simply means the branch of mathematical logic that deals with sets, that can be described as collections of objects.
It should be noted that perfect squares are the numbers that can be divided to give same number.
Q = {all perfect squares less than 30}. This will be 1, 4, 9, 16, 25
P ={ all odd numbers from 1 to 10}. This will be 1, 3, 5, 7, and 9.
In this case, the common numbers to set of P and Q are 1 and 9.
Therefore, the numbers are 1 and 9 since they're common to both sides.
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If Q = {all perfect squares less than 30} and p={ all odd numbers from 1 to 10}. Find Q ∩ P.
Answer:
He should have moved to the right.
Step-by-step explanation:
Ken moved 7 to the right which is correct because he needs to get 7º higher, but when he moved 2º to the left that would be a temperature decrease which is is incorrect.
Answer:
1. y' = 3x² / 4y²
2. y'' = 3x/8y⁵[(4y³ – 3x³)]
Step-by-step explanation:
From the question given above, the following data were obtained:
3x³ – 4y³ = 4
y' =?
y'' =?
1. Determination of y'
To obtain y', we simply defferentiate the expression ones. This can be obtained as follow:
3x³ – 4y³ = 4
Differentiate
9x² – 12y²dy/dx = 0
Rearrange
12y²dy/dx = 9x²
Divide both side by 12y²
dy/dx = 9x² / 12y²
dy/dx = 3x² / 4y²
y' = 3x² / 4y²
2. Determination of y''
To obtain y'', we simply defferentiate above expression i.e y' = 3x² / 4y². This can be obtained as follow:
3x² / 4y²
Let:
u = 3x²
v = 4y²
Find u' and v'
u' = 6x
v' = 8ydy/dx
Applying quotient rule
y'' = [vu' – uv'] / v²
y'' = [4y²(6x) – 3x²(8ydy/dx)] / (4y²)²
y'' = [24xy² – 24x²ydy/dx] / 16y⁴
Recall:
dy/dx = 3x² / 4y²
y'' = [24xy² – 24x²y (3x² / 4y² )] / 16y⁴
y'' = [24xy² – 18x⁴/y] / 16y⁴
y'' = 1/16y⁴[24xy² – 18x⁴/y]
y'' = 1/16y⁴[(24xy³ – 18x⁴)/y]
y'' = 1/16y⁵[(24xy³ – 18x⁴)]
y'' = 6x/16y⁵[(4y³ – 3x³)]
y'' = 3x/8y⁵[(4y³ – 3x³)]
Ethans is the correct one