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3 years ago

14

Find an ordered pair ( x,y ) that is a solution to the equation. 6x-y=1

1 answer:

tiny-mole [99]3 years ago

3 0

I think one could be (2, 11).

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Answer the question in the photo pls!

galben [10]

Answer:

6x + 2y

Step-by-step explanation:

3 0

2 years ago

Help with 3 problems! Worth 23 points!!!

kicyunya [14]

Answer:

1. b. the one with the v shape

2. b.

3. c.

Step-by-step explanation:

in every graph you should use the line test with is when you draw a line from top to bottom and if the line touches more then one dot or line on the graph it isnt not a function

3 0

3 years ago

What is the average of the first 50 positive odd integers

mote1985 [20]

I think that the answer is 25

7 0

2 years ago

Two collinear points on a line are given in the table below:

katrin [286]

Answer:

$(4,3)$ and $(7,2)$ do not lie on the line

Step-by-step explanation:

Given

$(0,0)\ and\ (2,1)$

Required

Determine which points that are not on the line

First, we need to determine the slope (m) of the line:

$m = \frac{y_2 - y_1}{x_2- x_1}$

Where

$(x_1,y_1) = (0,0)$

$(x_2,y_2) = (2,1)$

So;

$m = \frac{y_2 - y_1}{x_2- x_1}$

$m = \frac{1 - 0}{2-0}$

$m = \frac{1}{2}$

Next, we determine the line equation using:

$y - y_1 = m(x -x_1)$

Where

$m = \frac{1}{2}$

$(x_1,y_1) = (0,0)$

$y - y_1 = m(x -x_1)$ becomes

$y - 0 = \frac{1}{2}(x - 0)$

$y = \frac{1}{2}x$

To determine which point is on the line, we simply plug in the values of x to in the equation check.

For $(4,2)$

$x = 4$ and $y =2$

Substitute 4 for x and 2 for y in $y = \frac{1}{2}x$

$2 = \frac{1}{2} * 4$

$2 = \frac{4}{2}$

$2=2$

<em>This point is on the graph</em>

<em></em>

For $(4,3)$

$x = 4$ and $y = 3$

Substitute 4 for x and 3 for y in $y = \frac{1}{2}x$

$3 = \frac{1}{2} * 4$

$3 = \frac{4}{2}$

$3 \neq 2$

<em>This point is not on the graph</em>

<em></em>

For $(7,2)$

$x = 7$ and $y = 2$

Substitute 7 for x and 2 for y in $y = \frac{1}{2}x$

$2 = \frac{1}{2} * 7$

$2 = \frac{7}{2}$

$2 \neq 3.5$

<em></em>

<em>This point is not on the graph</em>

<em></em>

<em></em> $(\frac{4}{8},\frac{2}{8})$ <em></em>

<em></em> $x = \frac{4}{8}$ and<em> </em> $y = \frac{2}{8}$ <em></em>

<em>Substitute </em> $\frac{4}{8}$ <em> for x and </em> $\frac{2}{8}$ <em> for y in </em> $y = \frac{1}{2}x$ <em></em>

<em></em> $\frac{2}{8} = \frac{1}{2} * \frac{4}{8}$ <em></em>

<em></em> $\frac{2}{8} = \frac{1 * 4}{8 * 2}$ <em></em>

<em></em> $\frac{2}{8} = \frac{4}{16}$ <em></em>

<em></em> $\frac{1}{4} = \frac{1}{4}$ <em></em>

<em></em>

<em>This point is on the graph</em>

3 0

3 years ago

16,42 greatest common factor

kozerog [31]

2

42 ÷ 2 = 21
16 ÷ 2 = 8

Let's try the other factors of 42...

42 ÷ 6 = 7
16 ÷ 6 = 2.66
No...

42 ÷ 7 = 6
16 ÷ 7 = 2 2/7
No...

42 ÷ 14 = 3
16 ÷ 14 = 1.1428
No...

7 0

3 years ago