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2 years ago

On the first two downs, a football team lost a yard and then lost 2 yards.

Mathematics

1 answer:

postnew [5]2 years ago

8 0

First they lost 1 yard which would be written as -1

Next they let 2 yards which is written as -2

Now add them together: -1 + -2 = -3

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Answer:

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2 years ago

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Can someone please help me on this

Tanzania [10]

$a=2(-2)-1 = -4-1 =-5\\\\b=2(-1)-1 = -2 - 1 = -3\\\\c=2(1)-1 = 2-1 = 1\\\\d=2(2) -1 = 4 -1 =3$

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2 years ago

Gcf and lcm of 6 and 9

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2 years ago

The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an

Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = $\dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, w = $\dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}$

Or, w = $\dfrac{-11\pm \sqrt{473}}{2}$

or, w = $\dfrac{-11\pm 21.7}{2}$

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

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3 years ago

If log 3 = x and log 5 = y, express log 45 in terms of x and y.

Marysya12 [62]

Answer:

I believe that the answer is A

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1 year ago