To multiply factors of 10 (that's anything with zero on the end) just multiply the numbers that are NOT zeros on the end and then add the zeros back onto the answer. For example..
500 × 3
multiply 5 × 3 = 15 then add the 2 zeros back 1,500.
Your problem is 9 × 1000
9 × 1 = 9
add the three zeros back
9,000.
Answer:
What's your question?
Step-by-step explanation:
From 1st equation
d + e = 2
d = 2 - e
From 2nd equation, subtitute d with 2 - e
d - e = 4
2 - e - e = 4
2 - 2e = 4
-2e = 2
e = -1
Find d
d = 2 - e
d = 2 - (-1)
d = 3
The solution is (3,-1)
I am assuming you want to solve for x:-
Now cosec^2 2x = 1 - cot^2 2x so the equation becomes
3 cosec^2(2x) + 2 cosec 2x = cosec^2 2x
2 cosec^2 2x + 2 cosec 2x = 0
2 cosec 2x ( cosec 2x + 1) = 0
so 2 cosec 2x = 0 or cosec 2x = -1
cosec 2x = 0 or cosec 2x = -1
cosec 2x = 0 is indeterminate so we ignore the first one
cosec 2x = -1 can be written as 1 / sin 2x = -1
so sin 2x = -1
giving 2x = 270 degrees
Therefore x = 135 degrees answer