Answer:
χ²R = 8.643
χ²L = 42.796
0.20 < σ < 0.45
Step-by-step explanation:
Given :
Sample size, n = 23
The degree of freedom, df = n - 1 = 23 - 1 = 22
At α - level = 99%
For χ²R ; 1 - (1 - 0.99)/2= 0.995 ; df = 22 ; χ²R = 8.643
For χ²L ; (1 - 0.99)/2 = 0.005 ; df = 22 ; χ²L = 42.796
The confidence interval of σ ;
s * √[(n-1)/χ²L] < σ < s * √[(n-1)/χ²R)]
0.28 * √(22/42.796) < σ < 0.28 * √(22/8.643)
0.2008 < σ < 0.4467
0.20 < σ < 0.45
Answer:
Volume = 33.51 m^3
Step-by-step explanation:
<u>Formula for a Sphere: V = 4
/3 * π * r^3</u>
<u />
<u>Step 1: Plug in</u>
V = 4
/3 * π * (2)^3
V = 4/3 * π * 8
V = c
<em>V = 33.51</em>
<em />
Answer: Volume = 33.51 m^3
Answer:
9 groups with 6 extra students
Step-by-step explanation:
78/8= 9 .75
we take the whole number =9
8*9=72
78-72=6
6 extra students
Answer:
Step-by-step explanation:
I really don't have explanation on this.
Why, because it's too hard to explain.