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Anna71 [15]
3 years ago
8

What weighs more than a ton

Mathematics
1 answer:
erica [24]3 years ago
3 0
It is called a long ton which is 2,240 pounds where a ton is 2,000 pounds.\

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A wildlife shelter is home to birds, mammals, and reptiles. If cat chow is sold in 30 lb bags, what is the least number of bags
kotykmax [81]

Answer:

26 bags

Step-by-step explanation:

A bag of cat chows = 30 lbs

Amount of cat chows needed in a week = 15 lbs = ½ bag of cat chow

There are at least 52 weeks in a year.

The least number of cat chows bags needed at the shelter in 1 year = 52 weeks × ½ bag of chow

= 52 × ½

= 52/2

= 26 bags of cat chow

At least, 26 bags would be needed in 1 year (52 weeks) at this wild life shelter if 15 lbs is consumed weekly.

4 0
3 years ago
Read 2 more answers
What is the product? 3x^5(2x^2+4+1)
const2013 [10]

Answer:

6x^{7} +15x^{5}

Step-by-step explanation:

3x^{5}(2x^{2} +4+1)

Multiply 3x^{5} by each term in the parentheses.

6x^{7} + 12x^{5} +3x^{5}

Now, all you have to do is simplify.

6x^{7} +15x^{5}

5 0
3 years ago
PLS SOMEONE HELP I DO NOT UNDERSTAND PLS AND TY ASAP PLS PLS I WILL GIVE BRAINLIST AND PLS DONT BE A BOT
Kruka [31]

Answer:

35°

Step-by-step explanation:

The central arc is equal to the arc that subtends it, then

arc AC = 75° and

BC = AC - AB = 75° - 40° = 35°

8 0
2 years ago
How many different ways can you make 82 cents using current u.s. currency
andrew11 [14]
 <span>You can probably just work it out. 

You need non-negative integer solutions to p+5n+10d+25q = 82. 

If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80. 


So this is the same as n + 2d + 5q ≤ 16 

So now you simply have to "crank out" the cases. 

Case q=0 [ n + 2d ≤ 16 ] 

Case (q=0,d=0) → n = 0 through 16 [17 possibilities] 
Case (q=0,d=1) → n = 0 through 14 [15 possibilities] 
... 
Case (q=0,d=7) → n = 0 through 2 [3 possibilities] 
Case (q=0,d=8) → n = 0 [1 possibility] 

Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81 

Case q=1 [ n + 2d ≤ 11 ] 
Case (q=1,d=0) → n = 0 through 11 [12] 
Case (q=1,d=1) → n = 0 through 9 [10] 
... 
Case (q=1,d=5) → n = 0 through 1 [2] 

Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42 

Case q=2 [ n + 2 ≤ 6 ] 
Case (q=2,d=0) → n = 0 through 6 [7] 
Case (q=2,d=1) → n = 0 through 4 [5] 
Case (q=2,d=2) → n = 0 through 2 [3] 
Case (q=2,d=3) → n = 0 [1] 

Total from case q=2: 1 + 3 + 5 + 7 = 16 

Case q=3 [ n + 2d ≤ 1 ] 
Here d must be 0, so there is only the case: 
Case (q=3,d=0) → n = 0 through 1 [2] 

So the case q=3 only has 2. 

Grand total: 2 + 16 + 42 + 81 = 141 </span>
3 0
3 years ago
39.4 is what percent of 64 round to the nearest 100
Valentin [98]

Answer:61.7

Step-by-step explanation:

maths

4 0
2 years ago
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