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Georgia [21]
3 years ago
12

Thomas arrived at the library at 11:45 AMHe left 1 hour 40 minutes laterAt what time did Thomas leave the library?

Mathematics
1 answer:
andre [41]3 years ago
6 0

Answer:

At 1:25 P.M.

Step-by-step explanation:

Thomas arrived at the library at 11:45 AM and he left 1 hour 40 minutes later.

So, 1 hour 40 minutes is equivalent to (60 + 40) = 100 minutes.

Now, after 15 minutes, the time will be 12 P.M.

So, remaining (100 - 15) = 85 minutes i.e. 1 hour and 25 minutes the time will be 1:25 P.M.

Therefore, Thomas leaves the library at 1:25 P.M. (Answer)

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Sari has 3 times as many pencil erasers as Sam. Together, they have 28 erasers. How many erasers does Sari have?
BartSMP [9]

Let

x--------> amount of erasers that Sari has

y--------> amount of erasers that Sam has


we know that


x=3y-------> equation 1

x+y=28-----> equation 2


Substitute equation 1 in equation 2

[3y]+y=28\\ 4y=28\\ y=28/4\\ y=7


find the value of x

x=3y\\ x=3*7\\ x=21


therefore


the answer is

Sari has 21 erasers


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3 years ago
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A car travels 6 miles north and then turns right and travels 8 miles east to reach the garage. What is the straight line distanc
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6^2 + 8^2 = 100

\sqrt(100) = 10

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3 years ago
Please help due today!
Inessa [10]

Answer:

NO=22.6

Step-by-step explanation:

NO=MO+MN

after substituting MO and MN,

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4 years ago
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4. Find the mean absolute deviation (MAD) for the following data:
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The MAD is 2.4861 (1repeating) <span> I hope that helps :-) Good luck</span>
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Consider the function below. (If an answer does not exist, enter DNE.) f(x) = x3 − 27x + 3 (a) Find the interval of increase. (E
xxTIMURxx [149]

Answer:

(-∞,-3) and (3,∞)  

Step-by-step explanation:

f(x) = x³ − 27x + 3

1. Find the critical points

(a) Calculate the first derivative of the function.

f'(x) = 3x² -27  

(b) Factor the first derivative

f'(x)= 3(x² - 9) = 3(x + 3) (x - 3)

(c) Find the zeros

3(x + 3) (x - 3) = 0

x + 3 = 0      x - 3 = 0

     x = -3          x = 3

The critical points are at <em>x = -3</em> and x = 3.

2. Find the local extrema

(a) x = -3

f(x) = x³ − 27x + 3 = (-3)³ - 27(-3) + 3 = -27 +81 + 3 = 57

(b) x = 3

f(x) = x³ − 27x + 3 = 3³ - 27(3) + 3 = 27 - 81 + 3 = -51

The local extrema are at (-3,57) and (3,-51).

3, Identify the local extrema as maxima or minima

Test the first derivative (the slope) over the intervals (-∞, -3), (-3,3), (3,∞)

f'(-4) = 3x² -27 = 3(4)² - 27  = 21

f'(0) = 3(0)² -27 = -27

f'(4) = 3(4)² - 27 = 51

The function is increasing on the intervals (-∞,-3) and (3,∞).

The graph below shows the critical points of your function.

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3 years ago
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