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mr Goodwill [35]
3 years ago
8

A 30% acid solution was mixed with a 10% acid solution. The result was 600g of a 15% solution. How much of each solution was use

d for the mixture?

Mathematics
1 answer:
AlexFokin [52]3 years ago
3 0
____________________________________

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How should we prove this ?<br> Boc=90-1/2angle bac
Hatshy [7]

We have m(<CBO) = (1/2) · m(<CBE) = (1/2) · ( x + z );

In the same way, m(<BCO) = (1/2) ·( x + y);

m(<BOC) = 180 - [(1/2) · ( x + z ) + (1/2) ·( x + y)] = 180 - (1/2)· ( x + x + y + z );

But, x + y + z = 180;

Then, m(<BOC) = 180 - (1/2)·( x + 180 );

Finally, m(<BOC) = 90 - (1/2)·x;

So, m(<BOC) = 90 - (1/2)·m(<BAC).

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What is the difference between rational and irrational numbers
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An irrational number is a number which cannot be expressed in a ratio of two integers. In rational numbers, both numerator and denominator are whole numbers, where the denominator is not equal to zero. While an irrational number cannot be written in a fraction.
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4 years ago
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Suppose the life of a particular brand of calculator battery is approximately normally distributed with a mean of 75 hours and a
shepuryov [24]

Answer:

a) P(X

And we can find this probability using the normal standard table or excel:

P(z

b) P(X>77)=P(\frac{X-\mu}{\sigma}>\frac{77-\mu}{\sigma})=P(Z>\frac{77-75}{10})=P(z>0.2)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.2)=1-P(Z

c) z = \frac{70-75}{\frac{10}{\sqrt{16}}}= -2

z = \frac{80-75}{\frac{10}{\sqrt{16}}}= 2

And we can find this probability with this difference:

P(-2

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the life of a particular brand of a population, and for this case we know the distribution for X is given by:

X \sim N(75,10)  

Where \mu=75 and \sigma=10

Part a

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table or excel:

P(z

Part b

P(X>77)=P(\frac{X-\mu}{\sigma}>\frac{77-\mu}{\sigma})=P(Z>\frac{77-75}{10})=P(z>0.2)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.2)=1-P(Z

Part c

For this case we select a sample size of n =16. and we want this probability:

P(70 < \bar X

We know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we can find the z scores for the limits like this:

z = \frac{70-75}{\frac{10}{\sqrt{16}}}= -2

z = \frac{80-75}{\frac{10}{\sqrt{16}}}= 2

And we can find this probability with this difference:

P(-2

6 0
4 years ago
Need to find out the answer
lina2011 [118]

Answer:

I'm not sure, it looks like you do k12. Are u in 9th grade Algebra 1?

6 0
4 years ago
Read 2 more answers
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