What is the value of x in the equation 2x + 9 = 21? O2 06 09 O 15

Mathematics

1 answer:

Taya2010 [7]2 years ago

4 0

Answer:

the answer is 6

Step-by-step explanation:

2x + 9 = 21

2x = 21 - 9

2x = 12

x = 6

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Anastasy [175]

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3 years ago

the distribution of heights of adult American men is approximately normal with mean 68 in and a standard deviation of 2.5 in wha

melamori03 [73]

Let x be a random variable representing the heights of adult American men. Since it is normally distributed and the population mean and standard deviation are known, we would apply the formula,

z = (x - mean)/Standard deviation

From the information given,

mean = 68

standard deviation = 2.5

The probability that the height of a selected adult is between 63 and 73 is expressed as

$P(68\leq x\leq73)$

For x = 63,

z = (63 - 68)/2.5 = -2

Looking at the normal distribution table, the probability corresponding to the z score is 0.02275

For x = 73,

z = (73 - 68)/2.5 = 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.97725

Therefore,

$P(68\text{ }\leq x\leq73)\text{ = 0.97725 - 0.0}2275\text{ = 0}.9545$

Thus, the percentage of men are between 63 and 73 is

0.9545 * 100 = 95.45%

Rounding up to the nearest percentage, the answer is 95%

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1 year ago

Solve the equation for x by graphing -2x + 3 = -3(-x) - 2

adoni [48]

Answer:

x = 1

Step-by-step explanation:

There are a couple of ways to solve this. One is to graph the left side of the equation, graph the right side of the equation, and look for the point where those graphs intersect. It is at x = 1. The first attached graph shows this solution.

Another method for solving such an equation is to subtract one side from the other and look for the value of x that makes the resulting expression zero.

(-2x +3) -(-3(-x) -2) = 0

A graphing calculator doesn't need to have this simplified. If it is simplified, it becomes ...

-5x +5 = 0

So, the graphed line is y = -5x+5. Its x-intercept is x=1, the solution of the original equation. The graph of this is shown in the second attachment.